Wouldn't this be in literature?
Answer:
2y + 3 = 6
Step-by-step explanation:
2y + 3 = 6 <em>Subtract</em><em> </em><em>3</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em>
2y = 3 <em>Divide</em><em> </em><em>2</em><em> </em><em>from both</em><em> </em><em>sides</em>
y = 3/2
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Angles B and D are supplementary angles, so if B's angle is 30 degrees, then D's angle at y would be 150, since they have to add to 180.
In short, angle y = 150
Answer:
A
Step-by-step explanation:
