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ch4aika [34]
3 years ago
9

An explosion causes debris to rise vertically with an initial velocity of 160 feet per second. What is the speed of debris when

the height is 300 feet?
I am using the formula: -16t^2 + vot + h0 because the question is referring to feet.
Mathematics
1 answer:
lisov135 [29]3 years ago
5 0
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.  
We know there will be a constant downward acceleration of 32.15 ft/s^2.
 Use the following equation: 
 v_final^2 = v_initial^2 + 2ah
 v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
 v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
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Step-by-step explanation:

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Line segment AB has endpoints A(-1.5, 0) and B(4.5 8). Point C is on line segment AB located at (0, 2)
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We plug in the points to get:

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