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ch4aika [34]
3 years ago
9

An explosion causes debris to rise vertically with an initial velocity of 160 feet per second. What is the speed of debris when

the height is 300 feet?
I am using the formula: -16t^2 + vot + h0 because the question is referring to feet.
Mathematics
1 answer:
lisov135 [29]3 years ago
5 0
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.  
We know there will be a constant downward acceleration of 32.15 ft/s^2.
 Use the following equation: 
 v_final^2 = v_initial^2 + 2ah
 v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
 v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
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3 years ago
1. Grace was given the equation 2x + 20 = 15. She decides to add 10 to both sides of the equation. a.) Is that an acceptable mov
vlada-n [284]

9514 1404 393

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Step-by-step explanation:

Adding the same number to both sides of the equation is an acceptable move. The addition property of equality tells Grace that the value of the variable will remain unchanged by such a move.

Her new equation would be ...

  2x +20 +10 = 15 +10

  2x +30 = 25 . . . . the result of Grace's move

_____

<em>Additional comment</em>

There may be very good reasons why Grace would want to do that. If solving the equation is Grace's intent, that move would be counterproductive. For the purpose of solving the equation, it would be more productive to either subtract 20 from both sides, or divide both sides by 2. These steps would give, respectively, ...

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