All categories

2 years ago

A rhombus has diagonals 500 yd and 800 yd in length. Find the area in square miles.

1 answer:

7 0

1 mile = 1760 yd, so your area is ...
A = (1/2)×d₁×d₂
A = (1/2)×(500/1760)×(800/1760) mi²
A = 125/1936 mi²
A ≈ 0.0645661 mi²

You might be interested in

What is an equation of the line that passes through the point (2, -6) and is parallel

fomenos

Answer: y=-6

Step-by-step explanation:

First convert the equation -2y= 8 into y intercept form by divide both sides by -2.

-2y = 8

y= -4 Now that the line is in y intercept form we can now determine the slope.The slope is 0 so -4 in this case is the y intercept.

Remember lines that a parallel needs to have the same slope but different y-intercepts.

So if the slope of the line y=-4 is 0 then the slope of line that passes through the point (2,-6)

So using the y intercept form formula which says that y=mx+b where m is the slope and b is the y-intercept, we could plot in the values for y and x and solve for b to write the equation.

y is -6 and x is 2

-6 = 0(2) + b

-6 = 0 + b

b= -6

In this case the y intercept is -6 so since the slope is zero we will have the equation y = -6

5 0

2 years ago

.Divide the sum of 13/5 and -12/7 by the product of -31/7 and -(1/2)

andre [41]

Answer:

hello u so cool i admire you <3

6 0

2 years ago

Read 2 more answers

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

D = a person has the disease

X = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

2 years ago

What is the value of t=1 3(4 x (1/2) t-1)

Aliun [14]

Answer:

t = 13 over 25 or in alternate form its t = 0.52

7 0

3 years ago

Solve the equation. 5/7=10/x+2

skelet666 [1.2K]

Answer:

$x=-\frac{70}{9}$

Step-by-step explanation:

Isolate the variable by doing operations to both sides of the equation.

The work is shown below:

$\frac{5}{7} =\frac{10}{x} +2\\\\\frac{5}{7} - 2=\frac{10}{x} +2 - 2\\\\-\frac{9}{7} = \frac{10}{x}\\\\ -\frac{9}{7}*x = \frac{10}{x}*x\\\\ -\frac{9}{7}x = 10\\\\ -\frac{9}{7}x * (-\frac{7}{9})= 10 * (-\frac{7}{9}) \\\\x=-\frac{70}{9}$

6 0

2 years ago

Read 2 more answers