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gregori [183]
3 years ago
12

Students who apply to college in the summer after their senior year are considered for ___. A. rolling admission B. early addmis

sion C.regular admission or D. late admision
Advanced Placement (AP)
2 answers:
Hoochie [10]3 years ago
5 0
This really depends on the college/ university. Could be considered a rolling admission as well as a late admission. A college that participates in rolling admissions doesn't have a concrete deadline for applications. They are accepted until every space in the freshmen class is filled. Alternatively, late admission colleges have a concrete deadline for students who apply after the regular decision deadline has passed.
mel-nik [20]3 years ago
4 0

Answer:

D. late admission

Explanation:

-Rolling admission: is a policy in which colleges evaluate applications as they arrive until they fill all the places available.

-Early admission: is when a college accepts students to apply early in the year and they receive the results early.

-Regular admission: is the normal process in which students can send their applications until the due date set by the college and the answers are given no later than April 1st.

-Late admission: is the process in which some colleges accept applications after the due date has passed but the applications that arrived on time are processed first.

According to this, the answer is that students who apply to college in the summer after their senior year are considered for late admission.

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Answer:

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5 0
3 years ago
I will give branis what ever it’s called The rows in the periodic table are called periods.
Alona [7]
ITS B I’m pretty sure I had questions like this
7 0
3 years ago
Leila and Liam are twins and spent their 16th birthday at their favorite amusement park. After riding the biggest and fastest ro
Elan Coil [88]
Basilar membranes but not sure
3 0
3 years ago
A conical water tank is 24 ft high and has a radius of 10 ft at the top. If water flows into the tank at a rate of 20 cubic feet
Akimi4 [234]

Answer:

0.027 cubic ft/min

Explanation:

Volume of water is V=V(t) Depth of water is h=h(t)

The relationship between V and h is

V=π/3.r2.h

Let

h0= the height of the cylinder = 24ft, r0= the radius of the opening = 10ft.

Since water level (h) rise with respect to flow rate we find an expression for r and substitute into V

r/h = r0/h0= 10/24 = 5/12

r = (5/12) h,

Substitute for r in V

so,

V=1/3.π.(h2)square = 1/3.π. 25/144.(h3)

When

h= 16ft

and dV/dt = 20ft3/min

,

dV/dt =1/3*π*25/144*h3*(dh/dt)

20ft3/min= 1/3*π* 25/144*h3*(dh/dt)

20 = 1/3*π*(16)3.(dh/dt)

Make dh/DT subject of formula

dh/dt=(20*3*144)/(25*π*4096) = 8640/321740.8

=

dh/dt= 0.027 ft3/min

3 0
3 years ago
X-y=16 7x+2y=13 solving system of Equations by substitution
matrenka [14]

Answer:

The answer is "x= -\frac{19}{5} \ and \ y= - \frac{99}{5}"

Explanation:

\to x-y=16..........(a) \\\\ \to 7x+2y=13.........(b)\\

In equation (a) multiply by 2 then subtract from the equation (b):

7x+2y=13\\\\2x-2y=32\\\\- \  -\ =  -\ \\\\5x = -19 \\\\x= -\frac{19}{5}

put the value of x in equation (a):

-\frac{19}{5} -y=16\\\\ -y=16 +\frac{19}{5}\\\\-y=  \frac{80+19}{5}\\\\y= -\frac{99}{5}

6 0
3 years ago
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