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Triss [41]
4 years ago
11

Help please will give brainliest

Mathematics
1 answer:
FromTheMoon [43]4 years ago
3 0
The tangent line is perpendicular to the radius from the center of the circle to the point of tangency. 
ΔDCE is similar to ΔDBA
DC/DB=DE/DA
15/50=DE/40
DE=12 
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The function f(x) is a cubic function and the zeros of f(x) are −6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write
lys-0071 [83]

Answer:

6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

7 0
3 years ago
Pleas help due to night​
kati45 [8]
I can’t see the image to help u :(
5 0
3 years ago
Read 2 more answers
BRAINLIESTT ASAP! PLEASE HELP ME :)<br> thanks!!
Paraphin [41]

Answer:

third option

Step-by-step explanation:

<u>angle 1</u>

measure of angle 1 is diagonal to 45, theyre congruent angles

so measure of angle 1 is 45

<u>angle 2</u>

the sum of a triangle is 180 degrees

so for measure 2, we add 45 + 59 and we get 104. then we do 180 - 104 and we get 76

so the measure of angle 2 is 76

<u>angle 3</u>

since we know that the measure for angle 1 is 45, we can also solve for the measure of angle 3

to find angle 3, we do 55 + 45 and we get 100

and then you do 180 - 100 and you get 80

so the measure of angle 3 is 80

4 0
3 years ago
Write the equation, in slope-intercept form, of the line passing through the origin and the point $(-4,3)$.
netineya [11]
If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope m. To do that we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}.
From our two points we can infer that x_{1}=0, y_{1}=0, x_{2}=-4, y_{2}=3. Lets replace those values in the slope formula:
m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}
m= \frac{3-0}{-4-0}
m= \frac{3}{-4}
m=- \frac{3}{4}

Now that we have our slope, we can use the slope-intercept formula:
y-y_{1}=m(x-x_{1})
y-0=- \frac{3}{4} (x-0)
y=- \frac{3}{4} x

We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is y=- \frac{3}{4} x.

8 0
3 years ago
Ms. Bergstedt asked two students to come up with two different sequences. Jay created this sequence: The first term is 4 and eac
Roman55 [17]
Well, create an equation.


y=6x+4 and y=5x+8


From there you would go to Desmos.com and find out. The answer is 4,28.
This means it's the fourth term and the number is  28.
5 0
3 years ago
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