All categories

4 years ago

Help please will give brainliest

Mathematics

1 answer:

FromTheMoon [43]4 years ago

3 0

The tangent line is perpendicular to the radius from the center of the circle to the point of tangency.
ΔDCE is similar to ΔDBA
DC/DB=DE/DA
15/50=DE/40
DE=12

You might be interested in

The function f(x) is a cubic function and the zeros of f(x) are −6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write

lys-0071 [83]

Answer:

6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

7 0

3 years ago

Pleas help due to night

kati45 [8]

I can’t see the image to help u :(

5 0

3 years ago

Read 2 more answers

BRAINLIESTT ASAP! PLEASE HELP ME :) thanks!!

Paraphin [41]

Answer:

third option

Step-by-step explanation:

angle 1

measure of angle 1 is diagonal to 45, theyre congruent angles

so measure of angle 1 is 45

angle 2

the sum of a triangle is 180 degrees

so for measure 2, we add 45 + 59 and we get 104. then we do 180 - 104 and we get 76

so the measure of angle 2 is 76

angle 3

since we know that the measure for angle 1 is 45, we can also solve for the measure of angle 3

to find angle 3, we do 55 + 45 and we get 100

and then you do 180 - 100 and you get 80

so the measure of angle 3 is 80

4 0

3 years ago

Write the equation, in slope-intercept form, of the line passing through the origin and the point $(-4,3)$.

netineya [11]

If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope $m$ . To do that we are going to use the slope formula: $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ .
From our two points we can infer that $x_{1}=0$ , $y_{1}=0$ , $x_{2}=-4$ , $y_{2}=3$ . Lets replace those values in the slope formula:
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{3-0}{-4-0}$
$m= \frac{3}{-4}$
$m=- \frac{3}{4}$

Now that we have our slope, we can use the slope-intercept formula:
$y-y_{1}=m(x-x_{1})$
$y-0=- \frac{3}{4} (x-0)$
$y=- \frac{3}{4} x$

We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is $y=- \frac{3}{4} x$ .

8 0

3 years ago

Ms. Bergstedt asked two students to come up with two different sequences. Jay created this sequence: The first term is 4 and eac

Roman55 [17]

Well, create an equation.

y=6x+4 and y=5x+8

From there you would go to Desmos.com and find out. The answer is 4,28.
This means it's the fourth term and the number is 28.

5 0

3 years ago