Answer:
![\huge\boxed{V=44cm^3}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BV%3D44cm%5E3%7D)
Step-by-step explanation:
(look at the picture)
The formula of a volume of a rectangular prism a × b × c:
![V=abc](https://tex.z-dn.net/?f=V%3Dabc)
We have two rectangular prisms.
![1:\ 2cm\times2cm\times5cm\\2:\ 2cm\times2cm\times6cm](https://tex.z-dn.net/?f=1%3A%5C%202cm%5Ctimes2cm%5Ctimes5cm%5C%5C2%3A%5C%202cm%5Ctimes2cm%5Ctimes6cm)
Calculate the volume:
![V_1=2\cdot2\cdot5=20(cm^3)\\\\V_2=2\cdot2\cdot6=24(cm^3)](https://tex.z-dn.net/?f=V_1%3D2%5Ccdot2%5Ccdot5%3D20%28cm%5E3%29%5C%5C%5C%5CV_2%3D2%5Ccdot2%5Ccdot6%3D24%28cm%5E3%29)
The volume of the irregular figure:
![V_F=V_1+V_2\\\\V_F=20cm^3+24cm^3=44cm^3](https://tex.z-dn.net/?f=V_F%3DV_1%2BV_2%5C%5C%5C%5CV_F%3D20cm%5E3%2B24cm%5E3%3D44cm%5E3)
It is 8 percent of 50.
This is 1 way-
<span>4/50=%/100 You now have a proportion. Cross multiply.
50%=400 Replace % with any variable.
50x=400 Now divide both sides of the equation by 50.
x=8
</span><span>
(% is basically the percentage of 4 of 50 over 100. its much easier to solve </span>percentage problems when the percentages are over 100. 100 represents a full percentage.
example- 4 of 100 is 4% of 100)
2nd example-
Since the percentage can be found if over 100 as well (%/100), and since 100 is a multiple of 50, we can do 4 of 50 (which would look like 4/50) and multiply both numbers by 2 to get the percentage. These are our steps:
<u />4/50× 2/2=
8/100
Therefore, 4 of 50 is 8% of 50
Answer:
The formula for the sequence is: ![a_n = 2*(-3)^{n-1}](https://tex.z-dn.net/?f=a_n%20%3D%202%2A%28-3%29%5E%7Bn-1%7D)
Step-by-step explanation:
The general term of a geometric sequence is given by:
![a_n = a_1*r^{n-1}](https://tex.z-dn.net/?f=a_n%20%3D%20a_1%2Ar%5E%7Bn-1%7D)
In which
is the first term and r is the common ratio between the terms, that is, the division between them.
What is the formula for the sequence 2, -6, 18, -54, ...?
First term is 2, so ![a_1 = 2](https://tex.z-dn.net/?f=a_1%20%3D%202)
Common ratio is given by:
![r = \frac{-6}{2} = \frac{18}{-6} = ... = -3](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B-6%7D%7B2%7D%20%3D%20%5Cfrac%7B18%7D%7B-6%7D%20%3D%20...%20%3D%20-3)
So the sequence is given by:
![a_n = 2*(-3)^{n-1}](https://tex.z-dn.net/?f=a_n%20%3D%202%2A%28-3%29%5E%7Bn-1%7D)
Thanks bro, appreciate it
Answer:
12 mi.
Step-by-step explanation:
a^2+b^2=c^2
c is the hypotenuse (the line across the right angle) and a and b are the other sides.
a=5
c=13
Plug into the equation
5^2+b^2=13^2
b^2=169-25
b^2=144
b=12