Answer:
Graph A.
Step-by-step explanation:
The graph has a local minimum around x=-2 since it slightly curves downwards around this region. Moreover, the graph of the rational function has a horizontal asymptote at y=1 since the graph approaches this horizontal line but never touches nor crosses it
Answer:
False
Step-by-step explanation:
i did this question and got it right
Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC
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[ log (x) + log (y) = log (xy) ]
The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
See explanations below
Explanation:
Vertex of a graph is the lowest point on the curve. The vertex occurs at (1.75, -2.5)
The axis of symmetry is the point on the x axis of the line that cuts through the minimum point. The axis of symmetry occurs at x = 1.75
x intercept is the point where the curve cuts the x axis. The x intercept occurs at x = 0 and x = 2.5
To get the minimum, we will use the formula;
c - b^2/4a
The equation of the curve is expressed as;
(x-0)(x-2.5)
= x (x-2.5)
= x^2 - 2.5x
a = 1, b = -2.5, c = 0
minimum = 0 - (-2.5)^2/4(1)
minimum = -6.25/4
minimum = -1.5625
Minimum value occurs at the base of the parabola. The minimum value of the function is -2.5
y intercept is the point where the curve cuts the y axis. The y-intercept occurs at y = 0.
