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3 years ago

Please help me on this

Mathematics

2 answers:

Eddi Din [679]3 years ago

6 0

Answer:

The correct answer is True.

Step-by-step explanation:

Altitude: vertical distance either between the top and bottom of something or between a base and something above it.

dezoksy [38]3 years ago

6 0

The correct answer is true

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Using an example, explain what the graph of a rational function looks like. Contrast this with other functions we have studied.

Naddika [18.5K]

The graph of a rational function differs from that of other functions with the existence of asymptotes

<h3>Graph of rational functions</h3>

The properties of the graph of a rational function include;

The graph of a rational function never crosses its vertical asymptote
It crosses its horizontal or slant asymptote
The graph of the reciprocal function y = 1/x or y = k/x is a rectangular (or right) hyperbola of which asymptotes are the coordinate axes

The graph of a rational function differs from that of other functions with the existence of asymptotes.

Learn more about rational functions here:

brainly.com/question/1851758

#SPJ1

8 0

2 years ago

Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14

PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

$N(t)=N_{0}e^{-\lambda t}$

Where:

No = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

$\lambda$ = The decay constant.

One important parameter related to radioactive decay is the half-life:

$\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }$

If we know the value of the half-life, we can calculate the decay constant:

$\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}$

Carbon-14 has a half-life of 5,730 years, thus:

$\displaystyle \lambda=\frac {\ln(2)}{ 5,730}$

$\lambda=0.00012097$

The equation of the remaining quantity of Carbon-14 is:

$N(t)=N_{0}e^{-0.00012097\cdot t}$

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

$0.10N_o=N_{0}e^{-0.00012097\cdot t}$

Simplifying:

$0.10=e^{-0.00012097\cdot t}$

Taking logarithms:

$ln 0.10=-0.00012097\cdot t$

Solving for t:

$\displaystyle t=\frac{log 0.10}{-0.00012097}$

$t\approx 19,035\ years$

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0

3 years ago

Read 2 more answers

Tell whether the equation has one, zero, or infinitely many solutions.<br> 5(x – 7) + 5 = 5x – 30

Bezzdna [24]

Answer:

infinite solutions

Step-by-step explanation:

3 0

3 years ago

A. Original Price: $16.20

Tom [10]

Answer:

The final price is $ 22.68 And Proportional constant is 1.4

Step-by-step explanation:

Given as :

The Original price = $ 16.20

The rate of increase = 40%

Let The final price = x

Now,

Final price after increase = initial price × ( 1 + $\frac{\textrm Rate}{100}$

Or. Final price after increase = $ 16.20 × ( 1 + $\frac{\textrm 40}{100}$

Or, Final price after increase = $ 16.20 × ( 1.4 )

∴ Final price after increase = $ 22.68

Now , Proportional constant = $\frac{22.68}{16.20}$

I.e Proportional constant = 1.4

Hence The final price is $ 22.68 And Proportional constant is 1.4 Answer

4 0

3 years ago

Riley brought cupcakes to a party. by the end of the party 5/6 of the cupcakes were gone. what fraction of the cupcakes were lef

lions [1.4K]

Answer:

1/6

Step-by-step explanation:

this seems too simple but...

6/6 would be all the cupcakes the whole

so if 5/6 are gone than

1/6 are left

8 0

2 years ago

Read 2 more answers