27100(60)=815=1615 The 16 is how many minutes you have. If you were not given the seconds, we would have to say that we have a remainder of (1/5) of a minute. Since 1 minute is (1/60), one-fifth of that is (1/300). Now we would need to see how many seconds that gives us. 1 second is (1/3600) of a degree, so we would need to divide (1/300) by (1/3600). Doing this gives us: 1300÷13600=1300(3600)=12

5 0

3 years ago

Robert borrowed $750 from his parents. He promised to repay the loan by giving his parents at least $67 from his paycheck each w

Luda [366]

To answer this question we can propose the following equation:

$d=750 -x(67)$

Where:

x is the number of weeks elapsed.

d is the debt depending on the weeks.

Robert promised to pay at least $ 67 each week.

Therefore, after 5 weeks the debt of rober should be:

$d\leq750-5*67$

$d\leq415$

Then scenario A) is possible because $150$ .

After 6 weeks:

$d\leq750-6*67$

$d\leq348$

Then scenario B) is possible because $200$ .

After 7 weeks

$d\leq750-7*67$

$d\leq281$

Then scenario C) is possible because $250$ .

After 8 weeks

$d\leq750-8*67$

$d\leq214$

So scenario D) is NOT possible because $300>214$

Finally the correct answer is option D.

3 0

3 years ago

The population of Farmersville can be modeled by the inequality y > 2,000x + 2,100, where x is the number of years since 2010

Kaylis [27]

Answer:

The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.

Step-by-step explanation:

Inequality for the population of Farmsville:

The inequality for the population of Farmsville in x years after 2010 is given by:

$y(x) > 2000x + 2100$

Will the population of Farmersville be greater than 6,300 in 2012?

2012 is 2012-2010 = 2 years after 2010, so we have to find y(2).

$y(2) > 2000(2) + 2100$

$y(2) > 6100$

The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.

3 0

3 years ago