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3 years ago

Find the value of x. See attachment.

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

Answer:

x = 20

Step-by-step explanation:

the two angles form a complementary angle, which is 90 degrees, so you need to add them together.

x + 8 + 6x - 58 = 90

7x = 90 + 58 - 8

7x = 140

x = 20

you can plug x back in the equation to check your work

hope this helps! :)

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There was a country concert held at the park. For every 3 men there were 5 women that went to the concert. If 30 more women atte

8090 [49]

Answer:

3m == 5w, that means for such unit, there is a 2 person difference

30 person difference = 30/2 = 15units

and again one unit means 3m and 5w

so 15*3men, and 15*5women

and you can check the difference is 30

8 0

3 years ago

. The time required for a technician to machine a specific component is normally distributed with a mean of 2 hours and a standa

erma4kov [3.2K]

Answer:

a) There is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

b) There is a 0.42% probability that the technician will require at least 2.75 hours to complete one component

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have to be careful. The mean is in hours, while the standard deviation is in minutes. I am going to work with both in hours, as the problem states. 17 minutes is 0.283 hours, so:

$\mu = 2, \sigma = 0.283$

(a.) What is the probability that the technician can machine one component in 1.5 hours or less?

This probability is the pvalue of the Zscore when $X = 1.5$ . So:

$Z = \frac{1.5 - 2}{0.283}$

$Z = \frac{-0.5}{0.283}$

$Z = -1.77$

$Z = -1.77$ has a pvalue of 0.0384.

This means that there is a 3.84% probability that the technician can machine one component in 1.5 hours or less.

(b.) What is the probability that the technician will require at least 2.75 hours to complete one component?

The pvalue of the score of $X = 2.75$ is the probability that the technican will require less than 2.75 hours to complete one component. The probability that he will require at least 2.75 hours to complete one component is 1 subtracted by this pvalue. So: