Y = 4x + 2
y = 4×10 + 2
y = 42
the 10th term is 42
\left[y \right] = \left[ 0\right][y]=[0] I hope helping with u
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4
Therefore, the height of the building is 75.4 feet.
The number 16.177 is greater than the number 16.117 because it has a greater value in the hundredths column after the decimal point.
3 females 15 females
–––––––– = –––––––––
2 males n males
cross multiply
3n=15*2
3n=30
n=10
10 males
