Answer:
3/16
Explanation:
<u>According to Mendel's law of independent assortment of genes, when a dihybrid cross involves two genes that assort independently and one of the parents is dominant for the two genes and the other is recessive, the phenotypic ratio of the offspring at F2 would be 9:3:3:1</u>. The proportion of the offspring with the dominant parental traits would be 9/16, those with the recessive parental traits would be 1/16, while those with mixed traits would be 3/16 each.
Assuming the eye color is represented by E and the wing shape is represented by W. At F2
EeWw x EeWw
E_W_ - 9/16 (dominant for both eye color and wing shape)
E_ww - 3/16 (dominant for eye color and recessive for wing shape)
eeW_ - 3/16 (recessive for eye color and dominant for wing shape)
eeww - 1/16 (recessive for both eye color and wing shape)
<em>Hence, the proportion of the offspring with dominant phenotype for eye color and recessive phenotype for wing shape would be </em><em>3/16.</em>
Answer:
First, we take the owl out, the total number of mouse increases at a higher rate and the chipmunks are also decreasing in numbers. In an ideal ecosystem, both mice (lets call it "a") and chipmunks (lets call it "b") should increase since the restraining factor has been removed. But that is the opposite of what we should see. In that case, we will take the owl to be the "limiting factor" for the rodents.
Am
The rodents will have free movement and exercise their fitness over the area, competition sets in between the two species. So we see, a flourishes while b dies out. This can be viewed most predictably that a has an overall greater fitness and would easily get resources and strive readily, which influences the survival rate for 2.
Hope you got something in any realm of understanding?
Answer:
Explanation:
Molecular biology has enabled the identification of the mechanisms whereby inactive myostatin increases skeletal muscle growth in double-muscled (DM) animals. Myostatin is a secreted growth differentiation factor belonging to the transforming growth factor-β superfamily. Mutations make the myostatin gene inactive, resulting in muscle hypertrophy. The relationship between the different characteristics of DM cattle are defined with possible consequences for livestock husbandry. The extremely high carcass yield of DM animals coincides with a reduction in the size of most vital organs. As a consequence, DM animals may be more susceptible to respiratory disease, urolithiasis, lameness, nutritional stress, heat stress and dystocia, resulting in a lower robustness. Their feed intake capacity is reduced, necessitating a diet with a greater nutrient density. The modified myofiber type is responsible for a lower capillary density, and it induces a more glycolytic metabolism. There are associated changes for the living animal and post-mortem metabolism alterations, requiring appropriate slaughter conditions to maintain a high meat quality. Intramuscular fat content is low, and it is characterized by more unsaturated fatty acids, providing healthier meat for the consumer. It may not always be easy to find a balance between the different disciplines underlying the livestock husbandry of DM animals to realize a good performance and health and meat quality.
Answer:
Cytoplasm
Explanation:
Anaerobic respiration occurs in the cytoplasm. Fermentation enzymes are not restricted to specific organelles or cell structures. In contrast, aerobic respiration depends on mitochondria in eukaryotes and plasma membrane in prokaryotes.
It can't because the leaves are barriers.
