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insens350 [35]
4 years ago
9

Choose all the numbers that are perfect squares.

Mathematics
2 answers:
RoseWind [281]4 years ago
8 0
The answer is 64 which goes into evenly 8 times 8, 49 7 times 7, 4, 2 times 2, 144 12 times 12
VLD [36.1K]4 years ago
6 0
4, 49, 64, and 144 are all perfect squares. Because if you think back to it 2^2 is 4, 3^2 is 9, 4^2 is 16, 5^2 is 25. 6^2 is 36, 7^2 is 49, 8^2 is 64, 9^2 is 81, 10^2 is 100. 11^2 is 121. 12^2 is 144 and so on. 12, 24, and 84 do not show up in those numbers, so they are not perfect squares.
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Annita, Gary, and Tara all run races. Annita has 7 less than 4 times the number of race medals as Tara. Gary has 13 more than 2
harkovskaia [24]

Answer:

4 t - 7  = 2 t+ 13  is the required equation.

The number of race medals Tara has is t = 20 medals.

Step-by-step explanation:

Let the number of medals Tara has = t medals

So, the number of medal Anita has  = 4( Medals of Tara) - 7

= 4t - 7

And the number of medals Gary has = 2 times (Medals of Tara) + 13

= 2(t)  + 13  = 2t + 13

Now, Annita and Gary has same number of medals.

⇒  4t - 7  = 2t+ 13

or, 4t - 2t  = 7 + 13

⇒ 2t  = 20

⇒ t = 20/2 = 10

or t = 10

Hence, the number of race medals Tara has is t = 20 medals

6 0
3 years ago
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valentina_108 [34]

Answer:

x = 33

Step-by-step explanation:

8 0
3 years ago
2/3(3/5x+9)=1/2(2x+40)<br><br> I posted this before but w/o the 1/2 on accident
andriy [413]
The answer and working are shown in the photo below
5 0
3 years ago
our current account balance is $215. You have $322 of expenses each month. Your income is $444 per month. How long will it take
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8 0
3 years ago
Read 2 more answers
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
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integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
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7 0
3 years ago
Read 2 more answers
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