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gizmo_the_mogwai [7]
3 years ago
12

Angeles weather is making her a sandwich to take to school for lunch she is a loud to have two things on her sandwich and she ca

n choose from cheese tomato lettuce and ham how many choices does she have
Mathematics
2 answers:
cupoosta [38]3 years ago
6 0
There are 16 different combinations available.
FinnZ [79.3K]3 years ago
3 0
SHe has 4 choices chhese,tomato,lettuce,ham
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Show how to solve 304 take away 217
s344n2d4d5 [400]
You do 304 subtract 217 which equals 87
8 0
3 years ago
HELP PLEASE Connie can buy 48 roses for $120. Which is the cost per rose? A $1.20 B $2.50 © $3.00 D $4.00​
zubka84 [21]

Answer:

B: $2.50

Step-by-step explanation:

$120 ÷ 48 roses = cost per rose ($2.50)

4 0
3 years ago
What is the solution to 15 = d - 1 ?
Fofino [41]

Answer:

d = 16

Step-by-step explanation:

15 = d-1

Add 1 to each side

15 +1 =d-1+1

16 =d

8 0
3 years ago
Identify the new perimeter of the square using a scale factor of 1/3
Verizon [17]

Answer:

5

Step-by-step explanation:

15 × \frac{1}{3} = 5

5 0
3 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy
Debora [2.8K]

Answer:

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

df=n-1=28-1=27  

p_v =P(t_{(27)}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=60 represent the sample mean

s=8.9 represent the sample standard deviation

n=28 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:  

Null hypothesis:\mu \geq 63  

Alternative hypothesis:\mu < 63  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=28-1=27  

Since is a one side lower test the p value would be:  

p_v =P(t_{(27)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

5 0
3 years ago
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