Question

In a hospital ward, there are 12 nurses and 4 doctors. 3 of the nurses and 2 of the doctors are male. If a person is randomly selected from this group, what is the probability that the person is female or a doctor? @IMStuck @TheSaint905621 @Compassionate @phi @math&ing001 @acxbox22

Answer 1

Answer:  

$\bf \textbf{Probability that the person is female or a doctor = }\frac{13}{16}$

Step-by-step explanation:

Number of nurses in the hospital = 12

Number of doctors in the hospital = 4

Number of male nurses = 3

Number of male doctors = 2

Number of male persons = 5

So, Number of female persons = 16 - 5 = 11

Number of female doctors = 4 - 2 = 2

So, Probability that the person is female or a doctor = Probability that a person is female + Probability that a person is doctor - Probability that a person is female doctor

$\implies\text{Probability that the person is female or a doctor = }\frac{11}{16}+\frac{4}{16}-\frac{2}{16}\\\\\implies\bf \textbf{Probability that the person is female or a doctor = }\frac{13}{16}$

Answer 2

13/16
Because there are all together there are 16 people, 4 are doctors and 9 are female nurses. So add 9 and 4 are you get 13 since the question is asking for females or doctors.