Bruhhh 40 points if ansrew with work plus brainlest

10. The sum of three consecutive integers is 45. What are the three integers?

spayn [35]

Answer:

Step-by-step explanation:

The consecutive integers iincrease by 1. So the middle integer of an odd number of consecutive integers is their mean. Three is an odd number of integers.

45:3 = 15 ← middle number

15 - 1 = 14 ← the smallest number

15 + 1 = 16 ← the largest number

8 0

3 years ago

Step 3a: Calculating the average rate

Alex73 [517]

9514 1404 393

Answer:

a) average rate = (total distance)/(total time)

b) Rave = 2·R1·R2/(R1 +R2)

c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

First leg distance: AB = 70·t1 ⇒ t1 = AB/70

Second leg distance: AB = 40·t2 ⇒ t2 = AB/40

The average rate is the ratio of total distance to total time:

average rate = (AB +AB)/(t1 +t2)

average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

average rate = 560/11 = 50 10/11 . . . mph

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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

average rate = 2r1·r2/(r1+r2)

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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0

3 years ago

Correct answers for brainliest

alexandr402 [8]

Have you tried using
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A
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W
A
Y

6 0

3 years ago

Read 2 more answers

How do you simplify this expression step by step?

nataly862011 [7]

$\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{csc(\theta )-sin(\theta )}{cos(\theta )}\implies \cfrac{~~\frac{1}{sin(\theta )}-sin(\theta )~~}{cos(\theta )}\implies \cfrac{~~\frac{1-sin^2(\theta )}{sin(\theta )}~~}{cos(\theta )}$

$\bf \cfrac{1-sin^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{cos(\theta )}\implies \cfrac{\stackrel{cos(\theta )}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}} }{sin(\theta )}\cdot \cfrac{1}{\begin{matrix} cos(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\implies \cfrac{cos(\theta )}{sin(\theta )}\implies cot(\theta )$