Answer:
The side of first square =14 units
side of second square =4 units
Step-by-step explanation:
We have given two squares,
A square have all its four sides equal and at right angles.
Let the side of first square be 'a'
and the side of second square be 'b'
Given:
equation:1
equation:2
Solving equation:1
a=10+b equation:3
Putting 'a' in equation:2
Putting 'b' in equation:3
So, the side of first square is 14 units and
side of second square is 4 units
1st number = x
2nd number = y
2x + y = 26
-
x + y = 10
x = 16
26 - (2 x 16) = -6
10 - 16 = -6
Number 1 is 16
Number 2 is -6
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
[ y - 4 = x - 8 ] is not the equation of the line that goes through
those two points. The first point (8, 4) is on the graph of that
equation, but the second point (0, 2) is not.
The slope/intercept equation of the line that passes through
both points (8, 4) and (0, 2) is
y = 1/4 x + 2 .
The slope/intercept form of [ y - 4 = x - 8 ] is
y = x - 4 .
<span>The answer is 2 three-point shots. Since the Lakers made 37 two-point shots, one multiplies 37 by 2 (37 x 2), which equals 74. Then 74 is subtracted from the total 80 to see how many points are left (80 - 74), which equals 6. To determine the number of three-point shots, 6 is divided by 3 (6/3), which equals 2.</span>
