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Natali [406]
3 years ago
15

Sonoma bikes 5 miles to Paige's house. On a map, they measure that distance as 5/6cm. The same map shows that the mall is 3 1/2c

m from Paige's house. What is the actual distance between Paige's house and the mall?
Please show math
Mathematics
1 answer:
Elden [556K]3 years ago
7 0
Simplify fraction then subtract fractions
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Louis wants to carpet the rectangular floor of his basement. The basement has an area of 500 square feet. The width of the basem
Mazyrski [523]

Answer:

The correct answer is the length is 10 feet and width is 2 feet respectively.

Step-by-step explanation:

Let length of the rectangular floor of Louis' basement be l feet and width be \frac{l}{5} feet respectively.

Area of the basement floor is given to be 500 square feet.

Therefore according to the given problem,

l × \frac{l}{5}  = 500

⇒ l^{2} = 100

⇒ l = 10 ; [length cannot be negative]

⇒ b = 2

Thus the length and width be 10 feet and 2 feet respectively.

4 0
3 years ago
There’s this one as well
Doss [256]

Answer:

V= area of cross-section x length

V = 0.5x(8x9) x 11

V = 396cm^3

Hope this helps!

6 0
3 years ago
Trigonometry word problems
astraxan [27]

From a point on the ground 47 feet from the foot of a tree, the angle of elevation of the top of the tree is 35º. Find the height of the tree to the nearest foot.
7 0
3 years ago
Kevin made a jewelry box with the dimensions shown width: 15 cm length: 10 cm depth: 5 cm. what is the volume of the jewelry box
ziro4ka [17]

you need to know the mass of the jewelry box before you can know the volume but i can help you multiply th 15 and the 10 to get the mass most likely then divided what you have from 15 x 10 by the depth and you have your answer just be sure to round it off!


8 0
3 years ago
Read 2 more answers
Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, wha
Nutka1998 [239]

Answer:

See Explanation

Step-by-step explanation:

Given

Total = x^2 + 14x + 24

Area\ I = x^2

Area\ IV = 24

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

Total = x^2 + 14x + 24

And there are 4 areas, then;

Total = Area\ I + Area\ II + Area\ III + Area\ IV

Rewrite as:

Total = Area\ I + Area\ IV+ Area\ II + Area\ III

This gives:

x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III

Collect like terms

x^2 -x^2 + 14x + 24 -24=  Area\ II + Area\ III

14x =  Area\ II + Area\ III

Rewrite as:

Area\ II + Area\ III  = 14x

<em>So, the sum of areas III and IV must be 14x</em>

4 0
3 years ago
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