Question

Brian correctly use a method of completing the square to solve the equation X a 2nd plus 7X -11 equals zero Brian‘s first step was to rewrite the equation as extra 2nd+ 7X equals 11 he then added a number to both sides of the equation which number do you add

Answer 1

Answer:

$(\frac{7}{2})^{2}$

Step-by-step explanation:

Brain correctly use a method of completing the square to solve the equation:

$x^2+7x-11=0$

His First Step is to: Take the Constant Term to the Right Hand Side

$x^2+7x=11$

The Next Step Would be to:

• Divide the Coefficient of x by 2
• Square It
• Add it to both Sides

In this case, the Coefficient of x  = 7

• Divided by 2 = $\frac{7}{2}$

• Squaring It, we have: $(\frac{7}{2})^{2}$

It is this number $(\frac{7}{2})^{2}$ that is added to both sides in the manner below:

$x^2+7x+(\frac{7}{2})^{2}=11+(\frac{7}{2})^{2}$