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4 years ago

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Brian correctly use a method of completing the square to solve the equation X a 2nd plus 7X -11 equals zero Brian‘s first step w

as to rewrite the equation as extra 2nd+ 7X equals 11 he then added a number to both sides of the equation which number do you add

1 answer:

ArbitrLikvidat [17]4 years ago

6 0

Answer:

$(\frac{7}{2})^{2}$

Step-by-step explanation:

Brain correctly use a method of completing the square to solve the equation:

$x^2+7x-11=0$

His First Step is to: Take the Constant Term to the Right Hand Side

$x^2+7x=11$

The Next Step Would be to:

Divide the Coefficient of x by 2
Square It
Add it to both Sides

In this case, the Coefficient of x = 7

Divided by 2 = $\frac{7}{2}$

Squaring It, we have: $(\frac{7}{2})^{2}$

It is this number $(\frac{7}{2})^{2}$ that is added to both sides in the manner below:

$x^2+7x+(\frac{7}{2})^{2}=11+(\frac{7}{2})^{2}$

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