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3 years ago

Which following fractions is equivalent to 0.45

Mathematics

2 answers:

Stolb23 [73]3 years ago

8 0

Answer:

9/20

Step-by-step explanation:

plz giv me brainlist

vladimir1956 [14]3 years ago

6 0

0,45= $\frac{45}{100} =\frac{9}{20}$

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Ishaan is 72 years old and William is 4 years old. How many years will it take until Ishaan is only 5 times as old as William?

KiRa [710]

72+x=5(4+x) solve for x.

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3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

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3 years ago

Identify the independent variable and the dependent variable.

melamori03 [73]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is the distance from P to Q ?A. 7 unitsB. 5 unitsC. 1 unitD. 25 unitshow do I find the distance from P to Q?

Alex17521 [72]

to find the distance between 2 points we should apply the formula

$d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}$

call point q as point 1 for reference in the formula and p as point 2

replace the coordinates in the formula

$d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}$

simplify the equation

$\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}$

the distance between the 2 points is 5 units

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1 year ago

A survey among American adults concluded that 20% of adults believe Elvis is still alive, 10% believe they've been abducted by a

Kitty [74]

Answer:

$P(Alive\ or\ Aliens) = 26\%$

Step-by-step explanation:

Given

$P(Alive) = 20\%$

$P(Aliens) = 10\%$

$P(Alive\ and\ Aliens) = 4\%$

Required

Determine $P(Alive\ or\ Aliens)$

From laws of probabilities:

$P(A\ or\ B) = P(A) + P(B) - P(A\ and\ B)$

In this case:

$P(Alive\ or\ Aliens) = P(Alive) + P(Aliens) - P(Alive\ and\ Aliens)$

$P(Alive\ or\ Aliens) = 20\% + 10\% - 4\%$

$P(Alive\ or\ Aliens) = 26\%$

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3 years ago