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son4ous [18]
3 years ago
10

Which following fractions is equivalent to 0.45

Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0

Answer:

9/20

Step-by-step explanation:

plz giv me brainlist

vladimir1956 [14]3 years ago
6 0

0,45=\frac{45}{100} =\frac{9}{20}

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Solve the system:<br> 5x-7y=-41<br> -3x-5y=-3
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Answer:

x = -4 , y = 3

Step-by-step explanation:

5x - 7y = -41 ... (i)

-3x - 5y = -3 ... (ii)

Multiplying (i) by -3 and (ii) by 5 ;

-15x + 21y = 123 ... (i)

-15x - 25y = -15 ... (ii)

Subtracting (i) by (ii) ;

0 + 46y = 138

46y = 138

y = 138 ÷ 46 = 3

Returning to equation (ii) ;

-3x - 5(3) = -3

-3x = -3 + 15

-3x = 12

x = -4

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There are 2.54 centimeters to 1 inch. how many centimeters are in 15 inches
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How to solve for x:
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x = 2

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Find the area of the surface generated by revolving x=t + sqrt 2, y= (t^2)/2 + sqrt 2t+1, -sqrt 2 &lt;= t &lt;= sqrt about the y
EleoNora [17]

The area is given by the integral

\displaystyle A=2\pi\int_Cx(t)\,\mathrm ds

where <em>C</em> is the curve and dS is the line element,

\mathrm ds=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt

We have

x(t)=t+\sqrt 2\implies\dfrac{\mathrm dx}{\mathrm dt}=1

y(t)=\dfrac{t^2}2+\sqrt 2\,t+1\implies\dfrac{\mathrm dy}{\mathrm dt}=t+\sqrt 2

\implies\mathrm ds=\sqrt{1^2+(t+\sqrt2)^2}\,\mathrm dt=\sqrt{t^2+2\sqrt2\,t+3}\,\mathrm dt

So the area is

\displaystyle A=2\pi\int_{-\sqrt2}^{\sqrt2}(t+\sqrt 2)\sqrt{t^2+2\sqrt 2\,t+3}\,\mathrm dt

Substitute u=t^2+2\sqrt2\,t+3 and \mathrm du=(2t+2\sqrt 2)\,\mathrm dt:

\displaystyle A=\pi\int_1^9\sqrt u\,\mathrm du=\frac{2\pi}3u^{3/2}\bigg|_1^9=\frac{52\pi}3

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