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pashok25 [27]
3 years ago
14

If elf =gjh ef=12 and Lf=7.8 find ij

Mathematics
1 answer:
gavmur [86]3 years ago
8 0

Answer:

IJ= 4.98

Step-by-step explanation:

EF = 12

KF = 6

LF = 7.8

LK = sqrt(7.8^2-6^2) = 4.98

IJ = LK (4.98)

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Kelsey graphed the equation y = 3x + 1 as shown below.
USPshnik [31]

Answer:

D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.

Step-by-step explanation:

The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1

However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;

m=Δy/Δx  where

m=the slope of the graph

Δy= 3-0 =3

Δx= 0--3 =3

m=3/3 = 1

The equation of the line should be;

m=Δy/Δx

1=y-3/x-0

1x= y-3

3+1x= y

y= 1x + 3 ----------where the slope is 1 and y-intercept is 3

So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>

While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>

<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>

Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.

Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3

Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.

4 0
3 years ago
Read 2 more answers
The area of a square is 121 square feet. What is the perimeter of the square
Ugo [173]

Answer:

44 feet

Step-by-step explanation:

square root of 121 is 11

so each side of the square is 11

11 x 4 = 44

6 0
3 years ago
Hard math plz help!!!!!!!! PLZ NEED IT QUICK
Alex787 [66]

Answer:

Hi bub. Thanks for the points lol.

:D

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Directions: Use the figure to write the symbol for each.
choli [55]
These are my notes that you can use
5 0
3 years ago
PLEASE HELP!
Aleksandr-060686 [28]

The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3

<h3>How to create the sine function?</h3>

A sine function is represented as:

f(x) = A sin(B(x + C)) + D

Where

A = Amplitude

Period = 2π/B

C = Phase shift

D = Vertical shift

The requirements in the question are:

  • Amplitude not equal to 1
  • Period not equal to 2π
  • Non-zero phase and vertical shifts

So, we can use the following assumptions

A = 2

Period = 4

C = 6

D = -3

So, we have:

f(x) = 2 sin(B(x + 6)) - 3

The value of B is

4 = 2π/B

This gives

B = π/2

So, we have:

f(x) = 2 sin(π/2(x + 6)) - 3

<h3>The amplitude, vertical shift, period of f(x)and the phase shift</h3>

Using the representations in (a), we have:

  • Amplitude = 2
  • Vertical shift = -3
  • Period = 4
  • Phase shift = 6

<h3>The graph of the function</h3>

See attachment for the graph of f(x)

<h3>The value of cos θ </h3>

Let θ = 3π

So, we have:

cos(3π)

This is calculated as:

cos(3π) = cos(2π + π)

Expand

cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)

Evaluate

cos(3π) = -1

<h3>The value of sin θ </h3>

Let θ = 3π

So, we have:

sin(3π)

This is calculated as:

sin(3π) = sin(2π + π)

Expand

sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)

Evaluate

sin(3π) = 0

<h3>The value of tan 2θ </h3>

Let θ = 3π

So, we have:

tan(2 * 3π)

tan(6π)

This is calculated as:

tan(6π) = tan(3π + 3π)

Evaluate

tan(3π) = 0

Read more about sinusoidal functions at:

brainly.com/question/10700288

#SPJ1

6 0
1 year ago
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