Answer:
im not sure but i think its 225
Step-by-step explanation:5x5x3x3x1x1x1x1=225
<em>They took 101 peaches to market.</em>
<u>Check:</u>
In the 1st hour, they sold (101/2 + 1/2) = 102/2 = 51. They had 50 left.
In the 2nd hour, they sold (50/3 + 1/3)=51/3=17. They had (50-17)=33 left.
In the 3rd hour, they sold (33/4 + 3/4) = 36/4 = 9. They had (33-9) = 24 left.
In the final hour, they sold (24/5 + 1/5) = 25/5 = 5. They had (24-5) = 19 left. yay!
Fiona and Camilla took their 19 remaining peaches and went home. Sharing with
their parents and their brother Rowlf, each person had 3.8 peaches for dinner.
There was a lot of activity in the bathroom overnight.
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The key to solving this one is to work it backwards.
-- They had 19 peaches left at the end of the day.
-- During the final hour, the 1/5 of a peach that they sold left them with 19,
so they had 19-1/5 before they sold the 1/5 of a peach.
The 19-1/5 was 4/5 of what they had at the beginning of the final hour.
So, at the beginning of the final hour, they had (5/4)x(19.2) = 24 .
-- During the 3rd hour, the 3/4 of a peach that they sold left them with 24,
so they had 24-3/4 before they sold the 3/4 of a peach.
The 24-3/4 was 3/4 of what they had at the beginning of that hour.
So, at the beginning of the 3rd hour, they had (4/3)x(24.75) = 33 .
Do the same for the 2nd hour.
Then do the same for the 1st hour.
And you'll work your way back up to 101 peaches.
1 lb=16 oz
1 x 2.5=2.5 lb 16 oz x 2.5=40 oz
so 2.5 lb= 40 oz
Therefore, they weigh the same amount
The correct answers are, <u><em>A, D, and E.</em></u>
Answer:
Critical value: T = 1.8331
The 90% confidence interval for the population mean iron concentration is between 0.561 cc/m³ and 0.861 cc/m³
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.8331, which is the critical value.
The margin of error is:
M = T*s = 1.8331*0.0816 = 0.15
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.711 - 0.15 = 0.561 cc/m³
The upper end of the interval is the sample mean added to M. So it is 0.711 + 0.15 = 0.861 cc/m³
The 90% confidence interval for the population mean iron concentration is between 0.561 cc/m³ and 0.861 cc/m³
