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2 years ago

Need help ASAP!!!! Which two ratios form a proportion?

Mathematics

2 answers:

Alika [10]2 years ago

5 0

Answer:

Step-by-step explanation:

Pls make me brainliest

Galina-37 [17]2 years ago

4 0

Answer:

The answer is C 1/2 and 7/14

Two equivalent ratios for a proportion

To determine whether the two ratios form a proportion, you can compare them using a common denominator

1/2 = 7/14

1x7 = 7

2x7 = 14

7/14 = 7/14

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Dylan and Javier had the same size serving of vegetables for dinner. Dylan finished 2/3 of his vegetables. Javier ate 4/6 of his

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3 years ago

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Write two expressions to show w increased by 4.

iren2701 [21]

Answer:

4+w and w+4

Step-by-step explanation:

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3 years ago

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avanturin [10]

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2 years ago

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

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3 years ago