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Firlakuza [10]
3 years ago
10

How do you represent real-world problems involving ratios and rates with tables and graphs?

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0
Find the percentage of people with that problem or the percentage of it happening and put it in a circle graph like for example some people believe that certain vehicles shouldn't be allowed cause they cause population so i will put that percent in a circle graph and percent of people who think opposite
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Which expressions are equivalent to
REY [17]

Answer:

A,8,f,b

Step-by-step explanation:

8 0
1 year ago
Solve this! y- 5 = -12
vazorg [7]

The answer is -7 have a great day!

5 0
2 years ago
Read 2 more answers
Average rate of change help!!
frez [133]

Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

We need to determine the average rate of change over the interval 0 \leq x \leq 5

<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

f(0)=7

Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

f(5)=2

Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

Thus, the average rate of change over the interval 0 \leq x \leq 5 is -1.

3 0
2 years ago
A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an ineq
alukav5142 [94]

Answer:

13, 14

Step-by-step explanation:

The parameters of the numbers are;

A whole number value = 2 × Another number + 6

The sum of the two numbers is less than 50

Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number

Where 'x' represents the second number, we get;

x + 2·x + 6 < 50

Simplifying gives;

3·x + 6 < 50

x < (50 - 6)/3 = 14.\overline 6

x < 14.\overline 6

Therefore, the numbers for which the inequality holds true are numbers less than 14.\overline 6. From the given option, the numbers are 13, and 14.

3 0
3 years ago
What is the ratio of 3/20
Sveta_85 [38]
The ratio of 3/20 is 3:20
5 0
3 years ago
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