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poizon [28]
3 years ago
14

Find the diameter in units.

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

i think it’s 6.8 i’m not sure tho

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The values of w is inversely proportional to m .if w=8 then m=25; what is m when w=20?
iren2701 [21]

Answer:

m = 10

Step-by-step explanation:

Given w is inversely proportional to m then the equation relating them is

w = \frac{k}{m} ← k is the constant of variation

To find k use the condition w = 8, m = 25 , then

8 = \frac{k}{25} ( multiply both sides by 25 )

200 = k

w = \frac{200}{m} ← equation of variation

When w = 20 , then

20 = \frac{200}{m} ( multiply both sides by m )

20m = 200 ( divide both sides by 20 )

m = 10

3 0
3 years ago
What is 5 x 20 = what
vesna_86 [32]

Answer:

100.... my kind sir

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
To the nearest foot, what amount of fencing is needed to surround the perimeter of the flower bed? 17 feet 33 feet 40 feet 50 fe
KATRIN_1 [288]

We have two flower beds in this example, the first has a perimeter of 100 feet, and the second has a perimeter of 180 feet

The total is 280 feet

<h3>Perimeter of Rectangle</h3>

Given Data

Dimension of the first flower bed

Length = 17 feet

Width = 33 feet

Perimeter = 2L + 2W

Perimeter = 2*17 + 2*33

Perimeter =  34 + 66

Perimeter = 100 feet

Dimension of the second flower bed

Length = 40 feet

Width = 50 feet

Perimeter = 2L + 2W

Perimeter = 2*40 + 2*50

Perimeter = 80 + 100

Perimeter = 180 feet

The total length will be 100+180 = 280 feet

Learn more about Perimeter here:

brainly.com/question/19819849

4 0
2 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\&#10;y-5=\pm \sqrt{x-2}\\&#10;y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
–8(n + 7) &gt;-96??????????????
mihalych1998 [28]

Answer:

D) n<5

Step-by-step explanation:

4 0
2 years ago
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