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kvasek [131]
2 years ago
5

Please help me with these questions????​

Mathematics
1 answer:
Softa [21]2 years ago
3 0
5: THEO = what should happen
EXP = Wha actually happens.

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Answer: don't know sorry

Step-by-step explanation:

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2 years ago
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Please answer this in two minutes
NeTakaya

Answer:

15

Step-by-step explanation:

Use the Pythagorean Thereom:

r^{2} = 9^{2}+12^{2}

r^{2} = 81+144

r^{2} = 225

r= 15

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3 years ago
When homeowners list their home for sale, they begin by listing it for a price that is greater
Phantasy [73]

Answer:

-0.924

Step-by-step explanation:

The magnitude of the correlation coefficient is the square root of the variation.

|r| = √0.854

|r| = 0.924

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8 0
3 years ago
Plsssss help ASAP ;-;
lorasvet [3.4K]

Answer:

3x+2

Step-by-step explanation:

6x^{2} - 11x - 10 = (2x - 5)(3x+2)

So, \frac{6x^{2} - 11x - 10}{2x-5} = \frac{(2x-5)(3x+2)}{2x-5}

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5 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
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