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Ede4ka [16]
3 years ago
7

Steps to solve problem

Mathematics
2 answers:
Valentin [98]3 years ago
8 0
The you are asking for is is 239
RSB [31]3 years ago
3 0
Simplify 21+6 to 27
27x^9-4
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Determine and state an equation of the line perpendicular to the lines 5x-4y=10 and passing through the point (5,12). in point-s
sergey [27]
Perpendicular lines have slopes that are negative reciprocals of one another.

slope intercept form (y = mx + b) of the first equation will help us find the slope of the first line: where m = slope

5x-4y=10
-4y=-5x + 10
y=-5/-4 x + 10/-4
y=5/4 x -2.5

if the slope of this line is 5/4 then the slope of the perpendicular line is -4/5.

Therefore with the given information we can state the equation of the second line in point slope form (y-y,) = m(x-x,)

the coordinates of (5,12) can are substituted for x, and y,

so the answer is

(y-12) = -4/5(x-5)

I hope this helped and is BRAINLIEST!

Good luck with your studies!

8 0
2 years ago
Evaluate the expression.
AVprozaik [17]

Answer:

add my sc = bmic ava, no spaces

or add my discord = XoXo_ava

Step-by-step explanation:

Also have a great day and remember youre worth, dont let no boy/girl tear u down. leave them h*es aside and focus on yo self!!!

4 0
3 years ago
Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
miskamm [114]

Answer:

  114°

Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

  5x = 45 . . . . . . . . . divide by °, subtract 15+6x

  x = 9 . . . . . . . . . . divide by 5

The measure of exterior angle KMN is ...

  m∠KMN = (11(9) +15)° = 114°

_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

  60° +6x° +M = 180°

  (11x +15)° +M = 180°

Equating these expressions for 180° and subtracting M gives the relation we used above:

  (11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°

  (11x +15)° = 60° +6x° . . . . . . . . . . . subtract M

This is also described by "supplements to the same angle are equal."

4 0
2 years ago
Read 2 more answers
Find the coordinates of the image of a triangle with vertices A(0, – 3), B(3, 0), and
lora16 [44]

Answer:

A'(-3,0), B'(0,-3) and C'(4,7)

Step-by-step explanation:

We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).

We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.

90° clockwise about the origin

Rule:(x,y)\rightarrow (y,-x)

Using the rule

The coordinates of A'

A(0,-3)\rightarrow A'(-3,0)

The coordinates of B'

B(3,0)\rightarrow B'(0,-3)

The coordinates of C'

C(-7,4)\rightarrow C'(4,7)

Hence, the vertices of image of triangle is given by

A'(-3,0), B'(0,-3) and C'(4,7)

8 0
2 years ago
Divide: -84 by -7 A) -14 B) -13 C) 12 D) 13
rewona [7]
C.12

Divide
-84•/•7=12
5 0
3 years ago
Read 2 more answers
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