Perpendicular lines have slopes that are negative reciprocals of one another.
slope intercept form (y = mx + b) of the first equation will help us find the slope of the first line: where m = slope
5x-4y=10
-4y=-5x + 10
y=-5/-4 x + 10/-4
y=5/4 x -2.5
if the slope of this line is 5/4 then the slope of the perpendicular line is -4/5.
Therefore with the given information we can state the equation of the second line in point slope form (y-y,) = m(x-x,)
the coordinates of (5,12) can are substituted for x, and y,
so the answer is
(y-12) = -4/5(x-5)
I hope this helped and is BRAINLIEST!
Good luck with your studies!
Answer:
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Step-by-step explanation:
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Answer:
114°
Step-by-step explanation:
The exterior angle is the sum of the remote interior angles.
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<h3>setup</h3>
(11x +15)° = 60° +6x°
<h3>solution</h3>
5x = 45 . . . . . . . . . divide by °, subtract 15+6x
x = 9 . . . . . . . . . . divide by 5
The measure of exterior angle KMN is ...
m∠KMN = (11(9) +15)° = 114°
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<em>Additional comment</em>
Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...
60° +6x° +M = 180°
(11x +15)° +M = 180°
Equating these expressions for 180° and subtracting M gives the relation we used above:
(11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°
(11x +15)° = 60° +6x° . . . . . . . . . . . subtract M
This is also described by "supplements to the same angle are equal."
Answer:
A'(-3,0), B'(0,-3) and C'(4,7)
Step-by-step explanation:
We are given that the vertices of triangle are A(0,-3), B(3,0) and C(-7,4).
We have to find the coordinates of the image of triangle under a rotation of 90° clockwise about the origin.
90° clockwise about the origin
Rule:
Using the rule
The coordinates of A'

The coordinates of B'

The coordinates of C'

Hence, the vertices of image of triangle is given by
A'(-3,0), B'(0,-3) and C'(4,7)