CAN YOU READ THIS AND IF YOU CAN HELP ME!!!!! THIS CRAZY ONCE AGAINNNN I NEEDDDD PROFESSIONALLLL!!!!!!!!!!!!!

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

Pretty sure it’s D. hope this helps!

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Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0

2 years ago

I have 18 ones 15 hundreds 15 tens 8 thousands and 11 hundred thousands. What number am I?

levacccp [35]

The answer is 1,109,668 .
here is why:
18+ 1,500 is 1,518
1,518 + 150 is 1,668.
1,668+ 8,000 is 9,668
9,668 + 11,00,000 is 1,109,668
18 ones is 18. 15 hundreds is 1,500. 15 tens is 150. 8 thousands is 8,000. 11 hundred thousands is 1,100,000.

4 0

4 years ago

Read 2 more answers

What’s the anwers ? Need help

shusha [124]

5 because 2/6 of 24 is 8 and the difference of thirteen and 8 is 5

3 0

3 years ago

Read 2 more answers

100 points. Fun question to do.

Ganezh [65]

Answer: