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Lapatulllka [165]
3 years ago
13

Pls help I have no idea what I’m doing

Mathematics
1 answer:
olganol [36]3 years ago
8 0

Answer:

1800

Step-by-step explanation:

61 around to 60 and 29 rounds to 30. so

60 ×30=1800

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Answer this please thanks
Semmy [17]

Answer:

sixth degree because the highest degree is to the 6th and three terms

6 0
3 years ago
What is the answer for the equation 3(5k+2) + 5= 3k-1
mina [271]

Answer:

  • 12k + 12.

Step-by-step explanation:

=> 3(5k + 2) + 5 = 3k - 1

=> 15k + 6 + 5 = 3k - 1

=> 15k + 11 - 3k + 1

=> 12k + 12

<u>Hence, correct answer is 12k + 12.</u>

7 0
3 years ago
Read 2 more answers
Divide. Express the quotient in simplest form.
Scorpion4ik [409]
( \frac{x^2 - x -12}{2x} ) ÷ ( \frac{x^2 - 2x - 8}{4x^2} )

= ( \frac{x^2 - x -12}{2x} ) × ( \frac{4x^2}{x^2 - 2x - 8} )

= \frac{x(x^2 - x -12)}{x^2 - 2x - 8}

= \frac{x(x^2 -4x +3x -12)}{x^2 -4x +2x -8}

= \frac{x[x(x - 4) +3(x - 4)]}{x(x - 4) +2(x - 4)}

= \frac{x(x-4)(x+3)}{(x-4)(x+2)}

= \frac{x(x+3)}{(x+2)}
3 0
3 years ago
Reece is putting in a circular pool in his backyard. Th
pishuonlain [190]

Answer:

Step-by-step explanation:

we have to find out the circumference of the pool

C=2*3.14*r

d=36,   r=18

C=2*3.14*18=113.04 ft

3 0
3 years ago
Read 2 more answers
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6
faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0
4 years ago
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