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Mama L [17]
3 years ago
7

What is the solution to -(2x + 4) + x = 3x − 4x − 4?

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
7 0

Answer:

x=-2

Step-by-step explanation:

topjm [15]3 years ago
6 0

Answer:

all real numbers

Step-by-step explanation:

-(2x + 4) + x = 3x − 4x − 4

Distribute the negative sign on the left side. It is the same as having a -1 to the left of the parentheses.

-1(2x + 4) + x = 3x − 4x − 4

-2x - 4 + x = 3x - 4x - 4

Combine like terms on the left side. Combine like terms on the right side.

-x - 4 = -x - 4

Add 4 to both sides.

-x = -x

Add x to both sides.

0 = 0

You end up with a true equation. Therefore, there is an infinite number of solutions. Every real number is a solution.

Answer: all real numbers

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dezoksy [38]

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5+5=10

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Simplify. (y3)5 · y4
ICE Princess25 [194]

y^3 * 5 * y^4

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Helpp plzzz<br> Thank you
seropon [69]

Given:

32 and 28 are the two numbers.

To find:

(a) The GCF of 32 and 28.

(b) Using the GCF, find the factor of (32-28).

Solution:

(a)

The factor forms of the given numbers are:

32=2\times 2\times 2\times 2\times 2

28=2\times 2\times 7

It is clear that, 2 and 2 are the common factors in both.

GCF(32,28)=2\times 2

GCF(32,28)=4

Hence, the GCF of 32 and 28 is 4.

(b)

Using the GCF we need to find the factor of (32-28).

32-28=4\times 8-4\times 7

Taking out the GCF, we get

32-28=4\times (8-7)

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2 years ago
A school cafeteria in Quito made 62,800 lunches in one year.
Tasya [4]

Answer:

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According to a recent survey of adults, approximately 62% carry cash on a regular basis. The adults were also
pochemuha

According to the probabilities given, it is found that the correct option regarding the independence of the events is given by:

No, P(carry cash) != P(carry cash|have children).

<h3>What is the probability of independent events?</h3>

If two events, A and B, are independent, we have that:

P(A \cap B) = P(A)P(B)

Which also means that:

P(A|B) = P(A)

P(B|A) = P(B)

In this problem, we have that:

  • 62% carry cash on a regular basis, hence P(cash) = 0.62.
  • 46% has children, hence P(children) = 0.46.
  • Of the 46% who have children, 85% carry cash on a regular basis, hence P(cash|children) = 0.85.

Since P(carry cash) != P(carry cash|have children), they are not independent.

More can be learned about the probability of independent events at brainly.com/question/25715148

6 0
2 years ago
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