POINT A I had the same question in my math class !!!
<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
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Make bottom numbers same
convert to improper fraction
1 and 5/6=1+5/6=6/6+5/6=11/6
1/2 and 11/6
2 times 3=6
1/2 times 3/3=3/6
1/2+11/6=3/6+11/6=(4+11)/6=14/6
answer is A
False because you walk both the sides so you would have to do 360x2 added to 160x2
Answer:
to find range of interquartile sets of data
you see 5 vertical lines 1 is start point 2 is start of 2nd quartile 3 is start of 3rd quartile and also represents the median. the 4th start of 4th quartile and 5th is very end point.
Therefore the interquartile is from start line 2 to start line 4
apply to each by if it says 10 and 34 then we show workjings 34-10 = 24 and that is the range once we deduct data from each other.
Therefore full range is start line 1 to end line 5
if this says 2 to 45 then full range is 45-2 = 43 and apply to each boxplot.
Step-by-step explanation:
