The slop is 3 I hope that helped?
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Answer:
C) ∠C ≅ ∠C′
Step-by-step explanation:
The figures show a marked angle and side. To use AAS, we need another angle that is not adjacent to the marked side. That angle is C (or C'), so we require ...
∠C ≅ ∠C′
<span><u>Answer
</u>
Left border = 8 feet
Lower border =32 feet
Area=128 〖ft〗^2
<u>Explanation </u>
The area is a right triangle.
Let us take the left border to be y feet and the lower border to be x feet
Area=1/2 yx
The cost of fencing would be 4y+x=64.
From this expression x=64-4y
Substituting this value of x in the area we have;
Area=1/2 y(64-4y)
A=32y-2y^2
To get the maximum area of the triangle the first derivative of the area would te equal to zero.
A=32y-2y^2
dA/dy=32-4y=0
4y=32
y=8
Since x=64-4y
x=64-(4×8)=32
The dimensions of the garden are 8 feet by 32 feet.
Since the garden is a right triangle,
Area=1/2×8×32
Area=128 〖ft〗^2
</span>
If this is a system of equations then:
Multiply 5x-y=3 by -2
=> -10x+2y=-6
Now you sum the equations:
10x-10x+7y+2y=-3-6
=> 9y=-9
Then just divide by 9: y=-1
Now to get x, choose one of the equations and use the value we got from y:
5x-(-1)=3 => 5x+1=3 => 5x=3-1
=> 5x=2
=> x=2/5
(x,y)=(2/5, -1)
Answer:
Pigeonhole Principle
Step-by-step explanation:
From series {1,2......2n} ; we need to select 'n + 1' integers.
Even integers series from above series = {2,4,6..........2(n-1), 2n}
Odd integers series from above series = {1,3,5........2(n-2), 2n-1}
So, we can choose only n odd integers from the series. Hence, if we choose n+1 integers, atleast one of them have to be even integer.
- Eg : n = 5, Series = (1,2,3,4,5,6,7,8,9,10}, Odd series = {1,3,5,7,9}, Even series = {2,4,6,8,10}. If we choose 5 +1 ie 6 integers, there must be one even integer, as there are only 5 total odd integers in series.
