Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
Answer: B (x,y) --> (x + 4, y - 2)
Step-by-step explanation: When you add -5+4=-1, and when you subtract 2 from 4 it equals to 2, which gives you the second coordinates, this means that x+4 and y-2 is the answer.
![\sqrt[12]{2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B12%5D%7B2%7D%20)