Given that S<span>am's distribution of meal costs has a mean of $9 and a standard deviation of $3, this means that the range of Sam's meal cost that are within one standard deviation is given by ($9 - 3, $9 + 3) = ($6, $12).
Given that Sam </span><span>always tips the server $2 plus 10% of the cost of the meal, this means that when the cost of the meal is $9, Sam tips $2 + (0.1 x 9) = $2 + $0.9 = $2.90
Therefore, the mean of the distribution of Sam's tips is $2.90
Similarly, the </span><span>range of Sam's tips that are within one standard deviation is given by ($2 + 0.1(6), $2 + 0.1(12)) = ($2 + 0.6, $2 + 1.2) = ($2.6, 3.2) = ($2.9 - $0.3, $2.9 + $0.3)
Therefore, </span><span>the standard deviation of the distribution of Sam's tips is $0.3</span>
I need those points so bad I don’t know the answer sorry
Simplify the like variables
3c-7c = -4c
5d +d= 6d
10 will not be changed bc it doesn't have any alike variables
your answer: -4c+6d+10
Answer:
sin β = 0.92
Step-by-step explanation:
- sin β =
- sin β =
- sin β = 0.92
Answer:The answer is t=-12
Step-by-step explanation: First you have to simplify so the 4 is now positive. 2(t+18)+4, Subtract 4 from both sides.
2(t+18)=16−4
=12, 2(t+18)=12, now you have to divide both sides by 2. 2t/2=t and 12/2=6. t+18=6 now just subtract 18 from both sides. 18-18=0, 6-18=-12. So the answer is t=-12.
