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vladimir1956 [14]
3 years ago
11

What are the divisors of 12,300

Mathematics
2 answers:
Sidana [21]3 years ago
7 0
1, 2, 3, 4, 5, 6, 10.


Hope this helps :)
Sav [38]3 years ago
6 0

Answer:

1,2,3,4,5,6,10

Step-by-step explanation:

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Es
docker41 [41]

Answer:

x can be any value

Step-by-step explanation:

x can be any value and its output is always a constant 8.

4 0
3 years ago
Find the area of the circle and enter your answer below. Leave Pl in the answer (do not multiply by Pl) Area = πm2 15 m​
jolli1 [7]

Answer:

225π

Step-by-step explanation:

Since we are given that m is equivalent to 15 we can plug it into the Area equation given to us like so:

Area = πm²

Area = π15²

Area = π225

4 0
2 years ago
Find this area <br> A) 492.5ft2<br> B) 508.2ft2<br> C) 515.3ft2<br> D)551.6ft2
kap26 [50]
I think it’s A I’m sorry if I am wrong so I am pretty sure it’s A
4 0
3 years ago
HELPPP PLEASEEE!! This is due later tonight and I’m struggling! I’ve missed a few days of school from sickness! Help a girl out!
tekilochka [14]
10. 8x+4y=4. y=mx+b
-8x. -8x
4y=-8x+4
÷4. ÷4. ÷4
y = -2x +1
slope = -2. y-int= 1

11. slope is changing y over changing x
m = (y2 -y1)/(x2-x1) (0,-1) x1 = 0, y1=-1
(-4-(-1))/(-2-0) (-2,-4) x2 = -2, y2 = -4
(-4 + 1) / (-2)
-3/-2 = 3/2 answer is 3/2
12. b because negative cause it flip in x axis and it become flatter because of the fraction.
13. 2y =8-8x
÷2. ÷2 ÷2
y = 4 - 4x
Answer A
14. B
6 0
3 years ago
Find the least common multiple of each pair of polynomials.<br> 5 y² - 80 and y + 4
kobusy [5.1K]

The least common multiple of each pair of the polynomial (5y² - 80) and

(y + 4) is equal to 5(y-4)(y+4).

As given in the question,

Given pair of the polynomial is (5y² - 80) and (y + 4)

Simplify the given polynomial using (a² -b²) = (a-b)(a +b)

(5y² - 80) = 5(y² -16)

⇒(5y² - 80) = 5(y² - 4²)

⇒(5y² - 80) = 5(y -4)(y + 4)

And  (y + 4) = (1) (y+4)

Least common multiple = 5(y-4)(y+ 4)

Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).

Learn more about least common multiple here

brainly.com/question/11533141

#SPJ4

6 0
1 year ago
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