Answer:
82.79MPa
Step-by-step explanation:
Minimum yield strength for AISI 1040 cold drawn steel as obtained from literature, Sᵧ = 490 MPa
Given, outer radius, r₀ = 25mm = 0.025m, thickness = 6mm = 0.006m, internal radius, rᵢ = 19mm = 0.019m,
Largest allowable stress = 0.8(-490) = -392 MPa (minus sign because of compressive nature of the stress)
The tangential stress, σₜ = - ((r₀²p₀)/(r₀² - rᵢ²))(1 + (rᵢ²/r²))
But the maximum tangential stress will occur on the internal diameter of the tube, where r = rᵢ
σₜₘₐₓ = -2(r₀²p₀)/(r₀² - rᵢ²)
p₀ = - σₜₘₐₓ(r₀² - rᵢ²)/2(r₀²) = -392(0.025² - 0.019²)/2(0.025²) = 82.79 MPa.
Hope this helps!!
What are the answer choices
Answer:
guess and check
Step-by-step explanation:
Linear equation systems usually have two or more variables to find.
The values for these variables can be found by different methods, some of them are indeed graphing, substitution and with matrices.
So these are correct options that are used to solve linear systems of equations.
On the other hand, the guess and check method is not used to find the solution of these systems, since the more variables the system has the more difficult it is to guess the answer,<u> the graphic and mathematical methods are more effective and reliable.</u>
