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dangina [55]
2 years ago
5

Find dy/dx for the function y+4x²

Mathematics
1 answer:
docker41 [41]2 years ago
8 0

\dfrac{\partial }{\partial x}(y+4x^2)=0+8x=8x

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The difference between the roots of the quadratic equation x^2−14x+q=0 is 6. Find q.
lara31 [8.8K]

Answer:

q=-1128/169

Step-by-step explanation:

x²n-14x+q=0 here a=1, b= -14, c=q

let the roots of the equation beα and β

then the sum of the roots= S= α+β= -b/a=-(-14)/1=14

α+β=14 ⇒β=14-α--------(i)

product of the roots=P= αβ= c/a= q/1=q------(ii)

since α-β=6--------(given)----(iiI)

put the values of β from equation i to equation iii

α-14α=6

-13α=6

α=-6/13

put the values of α and β in eq. (ii)

αβ=q=(-6/13)(14-(-6/13)

q=(-6/13)(182+6/13)

q=(-6/13)188/13

q=-1128/169

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Which of the following functions are continuous. Select all that apply.
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