D. Because an amino acid is a monomer of a protein, meaning when a bunch of them are put together it’s a protein. And so it is when a bunch of monosaccharides are put together, it makes a polysaccharide
Should be Eukarya, I think
Insect populations can develop resistance to insecticides over time. The evolution of resistance is associated with an increase in the frequency of adaptive genes in the population.
- In the case above described it is expected that a few mosquitoes in the population were resistant to DDT before it was ever used (Option a is correct).
- Dichlorodiphenyltrichloroethane (DDT) is a pesticide used in agriculture.
- After exposure to DDT, those individuals in the mosquito population that didn't carry gene variants (i.e., alleles) associated with the resistance to this pesticide died.
- Subsequently, insects having adaptive alleles associated with DDT resistance survived and reproduced, thereby increasing the frequency of adaptive genes/alleles in the population.
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Answer:
It will not be significantly altered.
Explanation:
During an eight-hour fast glycolisis and cellular respiration will continue to function normally and the production of ATP would not be altered significantly, because there is a source of energy-rich molecules used in catabolism from glycogen stored in muscles and the liver, or fats stored in the fatty tissue or the muscle's protein themselves that can be used as a source of energy.
1. The answer is Telophase.
This is the last step of mitosis, during which the sister chromatids reach opposite poles. The small nuclear vesicles in the cell begin t reform around the group of chromosomes at each poles. Mitosis is a very important part of cell division because it is the process by which the parent cell gives its DNA to its two daughter cells.
2. The correct answer is 4. The cell would not be able to grow any further
Body cells divide by the process of mitosis; a process in which a body cells undergoes division tow yield two diploid daughter cells, the process enhances growth and development as the cell increase in number by multiplying themselves.
3. The correct answer Telophase II;
In prophase II, the nuclear envelop breaks down the spindle apparatus forms. The nuclear envelope forms around each set of chromosomes and cytokinesis occurs, producing four daughter cells, each with haploid set of chromosomes.
4. The answer is 4. its body cells would have 36 chromosomes and its gametes would have 18 chromosomes. The somatic cells or the body cells are cells that have diploid (two pairs of chromosome) number, while the gametes are formed from the process of meiosis and contains haploid number of chromosomes.
5. The best answer is ; meiosis ; it increases genetic variation, which helps ensure the species will survive. Meiosis is a type of cell division in which a cell (germ-line cells), where a cell divides to yield four daughter cells which are haploid; Meaning they have half the number of chromosomes as the parent cell.
6. The answer is 50 percent. If the dominant allele is Y and the recessive allele; Therefore; the heterozygous will be Yy and the homozygous green color will be yy.
Thus; A cross between heterozygous Yy and the green recessive yy will yield; 50 percent heterozygous and also half homozygous recessive.
7. The correct answer is that One parent was heterozygous for eye color and the other was homozygous with red eyes.
An organism can be homozygous dominant, if it carries two copies of the same dominant allele, or homozygous recessive, if it carries two copies of the same recessive allele. Heterozygous on the other hand, means that the organisms has two different alleles of a gene.
8. The correct answer is that the children will all have type AB blood. Both A and B alleles are dominant over O. as a result, individuals who have an AO genotype will have an A phenotype. The A and B alleles are codominant. When two alleles for a trait are equally expressed with neither being recessive or dominant, it creates codominance.
9. I believe the disease inheritance pattern described above by the cart shows Sex linked recessive inheritance pattern and in a cross between two heterozygous individuals there is a 50 percent chance for the second child born to be affected.
10. The answer for the question is 50 % percent.
I think that the infection design that is described above is a sex linked recessive legacy design and in a cross between two heterozygous individuals, there will be a half or 50 percent probability or possibility for the second child to be influenced.
