Question

Write an equation for the nth term of the arithmetic sequence. Then find a50. −29, −12, 5, 22, . . . an = a50 =

Answer 1

Answer:

             $\bold{a_n=17n+46}\\\\\bold{a_{50}=896}$

Step-by-step explanation:

−29, −12, 5, 22,  ...

-12-(-29) = 17;   5-(-12) = 17;   22-5 = 17  ⇒ d = 17

first term:  a = -29

difference:  d = 17

so the formula:

                         $a_n=a+d(n-1)\\\\a_n=-29+17(n-1)\\\\a_n =-29+17n-17\\\\\underline{a_n=17n+46}$                        

and:

   $a_{50}=17\cdot50+46=850+46 = 896$