The area ratio is 1:16 meaning that the old area is 1 while the new area is 16. So this is another way of saying "the area is multiplied by 16"
Take the square root of each part of the ratio of 1:16 and we get 1:4
So this is the scale factor. It tells us how the linear components of the circles relate to one another. If the circumference of the smaller circle is 1,then the larger circle has a circumference of 4.
Therefore, the circumference has been multiplied by 4
Answer: Question not very clear
Step-by-step explanation:
I will like to see the original question, then I will attempt to help you. Surely.
You need to add two mixed numerals.
One is positive and one is negative.
To add a positive number and a negative number, first take the absolute value of both, making them both positive. Then subtract the smaller absolute value from the larger absolute value. Finally, the sign of the answer is the same sign as the number that has the larger absolute value.
The numbers are -4 5/8 and 2 1/8
Take absolute values:
|-4 5/8| = 4 5/8
|2 1/8| = 2 1/8
Subtract the smaller absolute value from the larger absolute value.
4 5/8 - 2 1/8 = 2 4/8 = 2 1/2
The greater absolute value is 4 5/8.
Since the number with the larger absolute value was -4 5/8, a negative number, the answer is negative, -2 1/2
-4 5/8 + 2 1/8 = - 2 1/2
Using the quadratic formula, we have:

, so our solutions are

and

.
Answer:
Step-by-step explanation:
A ' = (-2, -3)
B ' = (0, -3)
C ' = (-1, 1)
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Explanation:
To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.
Algebraically, the reflection rule used can be written as
Applying this rule to the three given points will mean....
Point A = (-2, 3) becomes A ' = (-2, -3)
Point B = (0, 3) becomes B ' = (0, -3)
Point C = (-1, -1) becomes C ' = (-1, 1)
The diagram is provided below.
Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.