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deff fn [24]
3 years ago
8

How many solutions does a triangle with side lengths a = 4, A = 112º and b =9 have?​

Mathematics
1 answer:
Ainat [17]3 years ago
7 0

Answer:

This case has NO solutions.

Step-by-step explanation:

Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.

This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":

\frac{sin(A)}{a} =\frac{sin(B)}{b}\\sin(B)=\frac{b\,sin(A)}{a}\\sin(B)=\frac{9\,sin(112^o)}{4}\\\\sin(B)=2.086

As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).

Therefore, there is no angle we can find to build a triangle with the given data.

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Take the square root of each part of the ratio of 1:16 and we get 1:4

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If HK = 4p - 51 and JK = p, find the value of p in parallelogram GHIJ,<br> help !
MA_775_DIABLO [31]

Answer: Question not very clear

Step-by-step explanation:

I will like to see the original question, then I will attempt to help you. Surely.

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You need to add two mixed numerals.
One is positive and one is negative.
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Soloha48 [4]
Using the quadratic formula, we have:

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ch4aika [34]

Answer:

Step-by-step explanation:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as

Applying this rule to the three given points will mean....

Point A = (-2, 3) becomes A ' = (-2, -3)

Point B = (0, 3) becomes B ' = (0, -3)

Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

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