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ra1l [238]
3 years ago
11

Is 16 over 5 rational or irrational or not a real number

Mathematics
2 answers:
Semenov [28]3 years ago
8 0
It's rational. When you simplify 16^(1/2) / 5, you get 4/5. Therefore, it's rational. 
kotykmax [81]3 years ago
7 0
16/5= 3 1/5 
Rational
Irrational numbers never end and can't be written as a fraction. Ex. pi
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Share 66 g of sugar in the ratio 2:3:1?​
slega [8]

Answer:

whaaaaaaaaaattt????

Step-by-step explanation:

6 0
3 years ago
A triangle has one angle measuring 3x degrees. A second angle measures 2x + 20 degrees and the third angle measures 4x -20 degre
Maurinko [17]
All the interior angles of a triangle always add up to 180 degrees.

3x + (2x + 20) + (4x - 20) = 180
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4 0
4 years ago
Read 2 more answers
VI. PRACTICE TASKS
dimulka [17.4K]

Step-by-step explanation:

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8 0
2 years ago
I really need help with this Question don't know how to do it
suter [353]
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3 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
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