Add the lengths of all sides
A) x^2 + y^2 = 80
B) x * y = 12
What is x^2 -y^2?
B) x * y = 12
So y = 12 / x
A) x^2 + (12/x)^2 = 80
x^2 + (12/x)^2 = 80
x^2 + (144/x^2) = 80
Multiplying each side by x^2
x^4 + 144 = 80x^2
x^4 -80x^2 + 144 = 0
X = 1.355 (found by trial and error)
Y =
<span>
<span>
<span>
8.85608</span></span></span> (found by trial and error)
Answer:
RC = 40
Step-by-step explanation:
Note that the circumcentre is equally distant from the triangle's 3 vertices.
That is : PC = RC = QC
Equate any pair and solve for x
Using RC = PC, then
5x - 15 = 3x + 7 ( subtract 3x from both sides )
2x - 15 = 7 ( add 15 to both sides )
2x = 22 ( divide both sides by 2 )
x = 11
Hence
RC = (5 × 11) - 15 = 55 - 15 = 40 units
It’s either B or D. I’m sorry I’m not so sure but I think it’s either one of those.
I believe it's 5 to 9 since out of 9 games they win 5 and lose 4. This doesn't account for draws or anything, though.
