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Nutka1998 [239]
3 years ago
11

Graph -2x+10+5y=0 using intercepts. Add two intercept points on the graph.

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0
If you need any steps explained lmk

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PLZ CAN SOMEONE ANSWER THIS !!
Cerrena [4.2K]

Answer:

(-4,2)

Step-by-step explanation:

First we have to find a common multiple to use to add and find the system of equations. We need to eliminate one of the variables in order to solve.

Since 5 * 3 = 15, and 3 * -5 = 15, -15x and 15x will cancel each other out. Therefore x will be eliminated.

Before:

5x + 2y = -16

3x + 7y = 2

After:

15x + 6y = -48   <----------Now we solve for y

-15x + -35y = -10

+----------------------

-29y = -58

-29      -29

y = 2

Now what we do is we choose and equation and solve for x, since it is still unknown. Any equation is fine but I will choose the second one since it has easy numbers.

3x + 7y = 2

3x + 7(2) = 2

3x + 14 = 2

   -14     -14

----------------------

3x = -12

3        3

x = -4

Therefore our final answer is (-4,2)

5 0
3 years ago
A watering can dispenses water at the rate of 0.25 gallon per minute. The original volume of water in the can was 6 gallons. Whi
Monica [59]
At x=0 y=6 the y intercept. The rate is -0.25 so the equation is y=6-0.25x. The ordered pair is (x,6-0.25x).
3 0
3 years ago
Determine measurements of data for the following numbers:
Leno4ka [110]

Answer: mean=87, median=87.5 and range=18

Step-by-step explanation:

Mean:

First add all the numbers

78+95+77+92+87+79+94+86+88+94 = 870

Then you divide the answer by counting the numbers

870÷10

=87

Median:

First arrange the numbers in ascending order (from smallest to largest)

77, 78, 79, 86, 87, 88, 92, 94, 94, 95

pick the two middle numbers which is 87 and 88

then you do \frac{87+88}{2}

                = 175÷2

                =  87.5

range = Largest number - smallest number

= 95-77

= 18

8 0
3 years ago
A radar gun was used to record the speed of a swimmer (in meters per second) during selected times in the first 2 seconds of a r
Natalka [10]
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
0.8+2.24+1.75+0.7=5.49

5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
8 0
3 years ago
Surface area of a cylinder
Paul [167]
703.4 cmsquare
Hope it helps
4 0
3 years ago
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