Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.


Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as

by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
2n+9+5n=30 combine like terms on left side
7n+9=30 subtract 9 from both sides
7n=21 divide both sides by 7
n=3
19 yards divided by 2.5 minutes.
=19/2.5
= 7.6 yards/minute
Answer:
Well just gonna explain kn the bottom but the answer is 10
Step-by-step explanation:
what you would have to do first is to jusy do 5x4 which is 20 then since you wanna find the volume yoi qould juat do 200 divide by 20 which is 10
Answer:
it's an angle X duh he he he be