Garrett Jones gathered 97 bushels of oranges from his orange trees. How many pecks did he gather? How many quarts did he gather?

Mathematics

1 answer:

saveliy_v [14]3 years ago

3 0

Answer: Garrett Jones gathered 388 pecks of oranges.

Garrett Jones gathered 3104 quarts of oranges.

Step-by-step explanation:

Given: Garrett Jones gathered 97 bushels of oranges from his orange trees.

Since 1 bushel= 4 pecks

Therefore, 97 bushels = $4\times97=388\ \text{pecks}$

Hence, Garrett Jones gathered 388 pecks of oranges.

Also, 1 peck= 8 quarts

Therefore, 388 pecks= $8\times388=3104\text{ quarts}$

Hence, Garrett Jones gathered 3104 quarts of oranges.

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Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p

Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

$\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058$

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

$\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667$