Answer:
363.22
Step-by-step explanation:
<u>Method 1: </u>
You could find the whole figure surface area than divided by 1/2
<u>Method 2:</u> (the one I'm going to personally be doing)
Break the figure into two rectangular figures
Formula for surface area of rectangular prism:
A = 2(width x length + height x length + height x width)
Figure 1:
A = 2(width x length + height x length + height x width)
height = 3.8 yd
length = 10.1 yd
width = 4.3 yd
A = 2((4.3) x (10.1) + (3.8) x (10.1) + (3.8) x (4.3))
A = 2(98.15)
A = 196.3
Figure 2:
A = 2(width x length + height x length + height x width)
height = 8.4 yd
length = 10.1 yd
width = 2 yd
A = 2((2) x (10.1) + (8.4) x (10.1) + (8.4) x (2))
A = 2(121.84)
A = 243.68
There is overlapping surface area that shouldnt be include so we need to subtract it...
<u>For one face of figure 1</u>
3.8 x 10.1 = 38.38
Total:
Figure 1 + Figure 2 - 2(one face)
196.3 - 38.38 = 157.92
243.68 - 38.38 = 205.3
205.3 + 157.92 = 363.22
Because it was reflected across the x axis, the distance between the two points is twice the distance of the old point from the x axis, and the distance from the old point from the x axis equals the distance from the new point to the x axis. The distance from the x axis is the absolute value of the x=y value. 7.5 is the y value, meaning the point is 7.5 units away from y=0, the x axis. The new point is twice this from the old point. 7.5 x 2 = 15. The new point is 15 units away from the old point.
-1 is your x intercept so the first point is going to be at (0,-1) and from there go up 1 and over to the right 2 and mark another point and so one
Answer:
a range of values such that the probability is C % that a rndomly selected data value is in that range
Step-by-step explanation:
complete question is:
Select the proper interpretation of a confidence interval for a mean at a confidence level of C % .
a range of values produced by a method such that C % of confidence intervals produced the same way contain the sample mean
a range of values such that the probability is C % that a randomly selected data value is in that range
a range of values that contains C % of the sample data in a very large number of samples of the same size
a range of values constructed using a procedure that will develop a range that contains the population mean C % of the time
a range of values such that the probability is C % that the population mean is in that range
