In the triangle below, calculate the value of y.

Helpppppp show your work

Tpy6a [65]

Answer:

-5/3

Step-by-step explanation:

Do PEMDAS

8 - 11 = -3

-3 ^ 3 = -27

-(-27) = 27

I-14I = 14

3 x 14 = 42

27 - 42 = -15

2^4 = 16

16 - 7 = 9

-15/9 = -5/3

6 0

1 year ago

Read 2 more answers

Amir and Anna started driving from the same location. Amir 18 miles north and 18 miles west. Anna drove east and 18 miles north.

omeli [17]

They both drive 18 miles north, so if amir goes 18 miles west and Anna goes East, it is just 32 minus 18: she drove 12 miles east.

4 0

3 years ago

Two numbers have the same digits in the millions period, The same digits in the thousands period, and the same digits in the one

hjlf

Not unless the digits in each period are also in the same order. That is, the digit in each PLACE must be the same.

5 0

3 years ago

Can you help me with number 6? <br> Confused abit <br> Please

Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.

To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.

First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is

$\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}$

Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is

$\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}$

Third question:

To get exactly one six, it can either be the first, second or third roll.

In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.

In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus

$\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}$

And since there are three of these combinations, The answer is

$3\frac{5^2}{6^3}$

Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is

$1 - \frac{5^3}{6^3}$

4 0

3 years ago

What is the simplest form of

marusya05 [52]

Factor the numerator and factor the denominator.

$\frac{x^2 + 5x - 36}{x^2 - 16} = \frac{(x +9)(x - 4)}{(x + 4)(x - 4)} = \frac{x+9}{x+4}$

Then you divide the numerator and the denominator by the common factor to reduce the fraction.

7 0

3 years ago