Answer:
The correct option is;
C. Quadratic
Step-by-step explanation:
The given information are;
The quantity of corn Farmer Joe has to sell = 1,000 bushels
The present market price for corn = $5.00 a bushel
The amount by which he expects the market price to rise per week =$0.15
The number of bushels lost to spoilage per week = 10
Therefore, we have;
The value of the corn = Amount of corn left × Price of corn
The price of the corn per bushel with time = 5 + 0.15×t
The amount of corn left = 1000 - 10×t
Where;
t = Time in minutes
Therefore, the total value of corn = (1000 - 10×t)×(5 + 0.15×t) = -1.5·t²+100·t+5000 which is a quadratic model.
Therefore, the correct option is a quadratic model.
Answer:
3424
Step-by-step explanation:
42422434344
The tan(-x) is the same thing as -tan(x). The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
![[cos(x)][tan(-x)]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5Btan%28-x%29%5D)
is the same as
![[cos(x)][ -\frac{sin(x)}{cos(x)}]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5B%20-%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5D%20)
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.
The first one is 400, the second on is 40, and the last one is 4 *I hope this help u
The system of equations are p = 150 + 5n and p = 15n
<u>Solution:</u>
Given that, The Parks and recreation department in your town offers a season pass for $150.
With the season pass you pay $5 per session to use the town's tennis courts.
Without the season pass you pay $15 per session to use the tennis courts.
We have to write a system of equations to represent the situation
Now, let the number of sessions be "n" and total paying amount be "p"
<em><u>Then in case of taking season pass </u></em>
total amount = season pass cost + $5 per session
p = 150 + 5 x n
p = 150 + 5n
<em><u>And in case of no season pass</u></em>
total amount = 15 per session
p = 15 x n
p = 15n
Hence, the system of equations are p = 150 + 5n and p = 15n
