The simplified form of R(x) is 
<h3>Simplifying an expression </h3>
From the question, we are to simplify the expression
From the given information,

and

Also,

∴ 

Factoring each of the quadratics



Simplifying




Hence, the simplified form of R(x) is 
Learn more on Simplifying an expression here: brainly.com/question/1280754
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Answer:


Step-by-step explanation:
The law of indices can be used to simplify mathematical expressions involving arithmetical operation on variables with powers.
x
= 
Thus, the given expression can be simplified as follows:
a³b² a²b = a³ x a² x b² x 
=
x 
= 

Thus,
a³b² a²b = 

A. 36 square units
(Please tell me if I’m right in the comments)
Have a wonderful day!
Because both triangles appear to be isosceles!!!!!!???!!!!
Take L.H.S sin2A+sin2B/sin2A-sin2B
= sin2A+sin2B/sin2A-sin2B
Put
[sinC+sinD = 2sin(C+D)/2cos(C-D)/2]
[sinC-sinD = 2cos(C+D)/2.sin(C-D)/2]
= 2 sin(2A+2B)/2 cos(2A-2B)/2 / 2 cos(2A+2B) sin(2A-2B)
= sin(A+B).cos(A-B)/cos(A+B).sin(A-B)
= sin(A+B)/cos(A+B) . cos(A-B)/sin(A-B)
= tan(A+B).cot(A-B)
= tan(A+B).1/tan(A-B)
= tan(A+B)/tan(A-B)
∴ Hence we proved sin2A+sin2B/sin2A-sin2B=tan(A+B)/tan(A-B)