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shusha [124]
3 years ago
8

Dylan is planting flower boxes to decorate the school entrance. He has 64 marigolds and 72 periwinkles. Each flower box must con

tain both flowers. He puts the same number of marigolds in each flower box, and the same number of periwinkles in each flower box. What is the maximum number of flower boxes Dylan can plant and how many marigolds and periwinkles will each flower box have?
Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0

Answer:

Dylan can plant maximum 8 plants.

Number of marigolds in each flower box  =8

Number of periwinkles in each flower box  =9

Step-by-step explanation:

Number of marigolds = 64

Number of periwinkles = 72

To find the maximum number of flower boxes Dylan can plant, find H.C.F of 64 and 72.

64=2^6\\72=2^3\,\,3^2

So,

H.C.F(64, 72) = 2^3=8

That is Dylan can plant maximum 8 plants.

Number of marigolds in each flower box = \frac{64}{8}=8

Number of periwinkles in each flower box = \frac{72}{8}=9

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Read 2 more answers
F(t) = -(t-2) (t-15)
Goryan [66]

Answer:

smaller (t) = 2 and this in coordinates form (2,0)

larger (t) = 15 and this in coordinates form (15,0)

the vertex of the parabola =  (\frac{17}{2} ,\frac{169}{4} ) or in decimals (8.5, 42.25)

Step-by-step explanation:

  • For the zeros of the function take each bracket and make it equal to zero.

SMALLER (t):

(t-2)=0

(add 2 for both sides)

t=2

LARGER (t):

(t-15)=0

(add 15 for both sides)

t=15

  • For the vertex of the parabola you do:

step1: expand the brackets:

f(t)=-(t-2)(t-15)

f(t)= -t^{2} +17t-30

step2: define a,b and c using the expression ax^{2} +bx+c :

a= -1 (the coefficient of t^{2} )

b= 17 (the coefficient of t)

c= -30 (the single number without a letter)

step3: sub the values in the formula -\frac{b}{2a} to find the x coordinate of the vertex :

-\frac{b}{2a}

= - \frac{17}{2*-1}

= \frac{17}{2} or in decimals 8.5

step4: sub the value of t (the x-coordinate) in equation f(t):

f(t)= -t^{2} +17t-30

f ( \frac{17}{2})  = - (\frac{17}{2} )^{2}+ 17× \frac{17}{2} - 30

= -\frac{289}{4} + \frac{289}{2} -30

=\frac{169}{4} or in decimals 42.25

(THIS IS A PICTURE OF THE GRAPH↓)

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