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Paul [167]
3 years ago
9

Filtering removes data from the spreadsheet. A. True B. False

Computers and Technology
2 answers:
____ [38]3 years ago
5 0
6 is false
7 is false
8 is true
Y_Kistochka [10]3 years ago
4 0
<span>A cell has an unlimited number of conditions for Conditional Formatting.

A. True

B. False

This is  A. rue I just took the test
</span>
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Which of the following recommendations should you follow when placing access points to provide wireless access for users within
Colt1911 [192]

A WLAN, or wireless local area network, is created by an access point, typically in an office or big building. An access point transmits a Wi-Fi signal to a predetermined region after connecting via an Ethernet cable to a wired router, switch, or hub. Thus, option C is correct.

<h3>What access points to provide wireless access for users?</h3>

You may determine your wireless access point IP address by going to the settings menu of your adapter if you're already connected to the network via Wi-Fi or Ethernet.

Therefore, Open Network & Internet settings can be accessed by selecting with the right mouse click on the network icon in the system tray.

Learn more about wireless access here:

brainly.com/question/13073711

#SPJ1

6 0
1 year ago
Write a Java program to encrypt and decrypt a phrase using two similar approaches, each insecure by modern standards. The first
xeze [42]

Answer:

See explaination

Explanation:

//CryptoManager.java

public class CryptoManager {

static int LOWER_BOUND=32;

static int UPPER_BOUND=95;

/*This method determines if a string is within the allowable bounds of ASCII

codes according to the LOWER_BOUND and UPPER_BOUND characters. The parameter

plainText is the string to be encrypted. The method returns true if all

characters are within the allowable bounds, false if any character is outside.*/

public static boolean stringInBounds (String plainText)

{

boolean flag=true;

//determines if a string is within the allowable bounds of ASCII

//codes according to the LOWER_BOUND and UPPER_BOUND characters.

for(int i=0;i<plainText.length();i++)

{

if(!((int)plainText.charAt(i)>=LOWER_BOUND && (int)plainText.charAt(i)<=UPPER_BOUND))

{ //false if any character is outside the bounds

flag=false;

break;

}

}

//returns true if all characters are within the allowable bounds

return flag;

}

/*This method encrypts a string according to the Caesar Cipher. The integer key

specifies an offset and each character in plainText is replaced by the character

the specified distance away from it. The parameter plainText is an uppercase

string to be encrypted. The parameter key is an integer that specifies the

offset of each character. The method returns the encrypted string.*/

public static String encryptCaesar(String plainText, int key)

{

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//encrypted text

String res="";

//encryption

for(int i=0;i<plainText.length();i++)

{

res+=Character.toString((char) ((int)plainText.charAt(i)+key));

}

//return result

return res;

}

/* This method decrypts a string according to the Caesar Cipher. The integer

key specifies an offset and each character in encryptedText is replaced by

the character "offset" characters before it. This is the inverse of the

encryptCaesar method. The parameter encryptedText is the encrypted string

to be decrypted, and key is the integer used to encrypt the original text.

The method returns the original plain text string.*/

public static String decryptCaesar(String encryptedText, int key){

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//decrypted text

String org="";

//encryption

for(int i=0;i<encryptedText.length();i++)

{

org+=Character.toString((char) ((int)encryptedText.charAt(i)-key));

}

//return result

return org;

}

public static int Wrap_around(int key)

{

while(key>UPPER_BOUND)

{

key-=(UPPER_BOUND-LOWER_BOUND);

}

return key;

}

/* This method encrypts a string according to the Bellaso Cipher. Each character

in plainText is offset according to the ASCII value of the corresponding

character in bellasoStr, which is repeated to correspond to the length of

plaintext. The method returns the encrypted string.*/

public static String encryptBellaso(String plainText, String bellasoStr)

{

//encrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<plainText.length())

{

bellasoStr+=bellasoStr.substring(0,(plainText.length()-bellasoStr.length()));

}

//encryption

for(int i=0;i<plainText.length();i++)

{

char c=(char)Wrap_around((int)plainText.charAt(i)+(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

/*

This method decrypts a string according to the Bellaso Cipher. Each character

in encryptedText is replaced by the character corresponding to the character in

bellasoStr, which is repeated to correspond to the length of plainText. This is

the inverse of the encryptBellaso method. The parameter encryptedText is the

encrypted string to be decrypted, and bellasoStr is the string used to encrypt

the original text. The method returns the original plain text string.*/

public static String decryptBellaso(String encryptedText, String bellasoStr)

{

//decrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<encryptedText.length())

{

bellasoStr+=bellasoStr.substring(0,(encryptedText.length()-bellasoStr.length()));

}

//decryption

for(int i=0;i<encryptedText.length();i++)

{

char c=(char)Wrap_around((int)encryptedText.charAt(i)-(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

}

6 0
3 years ago
Jeff has created a table to calculate the cost of raw materials that he purchases monthly. Cell A2 shows the fixed cost of the r
Luda [366]
=A2*D2
The above formula will allow calculation  of monthly cost of the first raw material.This is done by Multiplying the contents of cell A2 (Column A, Row 2) and cell D2 (Column D, Row 2). Here Cell A2 contains cost of the first raw material and Cell D2 contains number of units of the raw material produced  each month. After finding the monthly cost of the first raw material in this way, the monthly cost of other raw materials can simply be calculated by dragging down the formula to apply to the rows below.
3 0
3 years ago
Read 2 more answers
your computer running Windows 10 is doing some very strange things with operating system you are fairly certain it is not a hard
AlekseyPX
It might be a virus, when my computer starts going crazy i just bought a fixme stick and they work amazing or trying getting an expert to fix it if it worse
6 0
3 years ago
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Choose all items that represent HTML characteristics.
hram777 [196]

Answer:

A,C,D,E are the answers at least on the test i took

Explanation:

3 0
3 years ago
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