Question

The variable grade can have any real number value from 0 to 100. Ask the user to enter a grade in numerical form. Write an if-elseif-else statement that displays the letter grade (any format) corresponding to a numerical grade in an appropriately formatted output statement. Use the standard 10-point grading scale:  a: A: 90 ≤ grade  a: B: 80 ≤ grade < 90  a: C: 70 ≤ grade < 80  a: D: 60 ≤ grade < 70  a: F: grade < 60

Answer 1

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

int main()

{

float marks;

cout<<"Enter your grade value :";

cin>>marks;

if(marks>=90)

cout<<"Your grade is 'A'";

else if(marks>=80&& marks<90)

cout<<"Your grade is 'B'";

else if(marks>=70&& marks <=80)

cout<<"Your grade is 'C'";

else if(marks>=60&& marks <70)

cout<<"Your grade is 'D'";

else

cout<<"Your grade is 'F'";

}